Neglecting end correction find the fundamental frequency of a tube of length 25 cm closed at one end. The velocity of sound in air is 340 m/s.
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A: Length of pipe (L) = 417 mm = 0.417 m Lowest resonant frequency = 228 Hz
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A: Required : Fill in the gaps
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Q: Ralph's ear canal is 2.67 cm long. If it is regarded as a tube that is open at one end and closed at…
A: Given, Length, L=2.67 cm=0.0267 m, and the speed of sound, v= 345 m/s.
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A: Given : f = 900 Hz vw = 15 m/s vs = 343 m/s
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A: We know that frequency f=v/λ
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Q: The sound intensity level inside a typical modern airliner inflight is 66.0 dB. The air in the cabin…
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Q: A tube open at both the ends has length 47 cm and its inner diameter is 5 cm. If the velocity of…
A: Length of tube L = 47 cm = 0.47 m Velocity of sound in air v = 330 m/s Inner diameter of tube D = 5…
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Q: (a) Find the length (in m) of an organ pipe closed at one end that produces a fundamental frequency…
A: Given Data: Frequency (f) = 262 Hz.Temperature 1 (T1) = 18.0o C.Temperature 2 (T2) = 28.0o C. To…
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A: The length of the air column is equal to one-fourth of the wavelength for the first harmonic. The…
Q: Calculate the frequency (in Hz) of the 2nd overtone emitted by an open pipe of length 1.5 m. The…
A: Given : An open pipe. Length, L = 1.5m Speed of sound in air, v = 343 m/s
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A: Given: Frequency=250Hz Velocity of sound in air=340m/s To find: shortest length of tube diamter 5cm
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Q: What is the frequency of the second overtone?
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Q: What length should an oboe have to produce a fundamental frequency of 110 Hz on a day when the speed…
A: Given data: Fundamental frequency is, f=110 Hz. Speed of sound is, v=343 m/s
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