NEGATIVE z Scores Standard Normal (z) Distribution: Cumulative Area from the LEFT .00 .01 .02 .03 .04 .05 .06 .07 .08 .09 -3.50 and lower .0001 .0003 .0003 0003 .0003 .0004 -3.4 .0003 .0003 .0003 .0003 .0003 .0002 -3.3 .0005 .0005 .0005 .0004 .0004 .0004 .0004 .0004 .0003 -3.2 .0007 .0007 .0006 .0006 .0006 .0006 .0006 .0005 .0005 .0005 -3.1 .0010 .0009 .0009 .0009 .0008 .0008 .0008 .0008 .0007 .0007 -3.0 .0013 .0013 .0013 .0012 .0012 .001 .001 .001 .0010 .0010 -2.9 .0019 .O018 .0018 .0017 .0016 .0016 .O015 .0015 .0014 .0014 -2.8 .0026 .0025 .0024 .0023 .0023 .0022 .0021 .0021 .0020 .0019 -2.7 .0035 .0034 .0033 .0032 .0031 .0030 .0029 .0028 .0027 .0026 -2.6 ,0047 .0045 .0044 .0043 .0041 .0040 .0039 .0038 .0037 ,0036 -2.5 .0062 .0060 .0059 .0057 .0055 .0054 .0052 .0051 * .0049 .0048 -2.4 .0082 .0080 .0078 .0075 .0073 .0071 .0069 .0068 .0066 .0064 -2.3 .0107 .0104 .0102 .0099 .0096 .0094 .0091 .0089 .0087 .0084 -2.2 .0139 .0136 .0132 .0129 .0125 .0122 .0119 .0116 .0113 .0110 -2.1 .0179 0174 .0170 .0166 .0162 .0158 .0154 .0150 .0146 .0143 -2.0 .0228 .0222 .0217 .0212 .0207 .0202 .0197 .0192 .0188 .0183 -1.9 .0287 .0281 .0274 .0268 .0262 .0256 .0250 .0244 .0239 .0233 -1.8 .0359 .0351 .0344 .0336 .0329 .0322 .0314 .0307 .0301 .0294 -1.7 .0446 .0436 .0427 .0418 0409 .0401 .0392 .0384 .0375 .0367 Print Done

Q: (-14) + (–7)

A:

Q: 1. Find L-¹{e-³s} 5}

A: We have to apply the inverse Laplace transform of the second shifting theorem to find the solution…

Q: V(3278)3 + 6230 – 12e90i

A:

Q: (4) y=x +4 -5 -4 -3 6.

A: The given equation is: y=x+4

Q: 10 14 9.) Find O 18

A:

Q: 1.25a +3> 0.5a-6 and 2.5a 129-1.5a

A:

Q: xp xペ-4xt13

A:

Q: こ (0) of

A:

Q: 9 – 4x > –3

A: The given inequality is 9-4x>-3

Q: If A: find A 2. 3 3. and Show Shat A-3

A: A=1213 Now determinant value is, A=13-12=1 Adjoint of matrix A is, adjA=3-2-11 Now,…

Q: х3 — 2х dx х — 1 -3 10. 2

A: Given: I=∫23x3-2xx-1dx For evaluating given integral, we substitute x-1=t…

Q: +–3m+–9m+4+5+–10m

A: The expression is given as 1+–3m+–9m+4+5+–10m. Simplifying the given expression. 1+–3m+–9m+4+5+–10m…

Q: 18) 2x y

A:

Q: Find A.

A:

Q: Evaluate. (3- 5)² + 4(1 – 5)

A: Given, (3-5)2 + 4(1-5)

Q: 0 1 2 4 0 2 4 0 0 3 9 12

A:

Q: 2(3+d-1)

A: Solve the given expression  given expression is 2(3+d-1)

Q: Find the LU factorization of A = A = 1 1 -3 0 9 3 -17 5 2

A:

Q: 2070 = (16a + 10)15

A: 2070 = (16a+10)15 And (16e+11)17 =3723 To find  the values of a and e

Q: 9. (x² – 2)3

A:

Q: 36-9z

A: Given that:36-9z

Q: 1 + 2n < n° for all integers n² 2

A:

Q: y27x+2

A: y &gt;= 7x/4 +2

Q: Identify the work done, J. F.dr by an electric field, E = (x + xy)î + (y + 5)f – 5zk V/m to move an…

A: Work done along the curve C by vector field F . Where C is given by parametric equation r(t)…

Q: Find A3 if A = {1, 2, a, b}

A: Given,      A=1, 2, a, b

Q: Evalvate S (4sin co) -8cos co) )do

A: Given that: ∫0π(4sinθ-8cosθ)dθ

Q: (1– 3csc(

A:

Q: S√4 4+² +3 dt

A:

Q: 75 + フチ + k「3

A:

Q: –4(–6m – 7).

A:

Q: 3. (x³ + 4x² –x – 1) + (x + 3)

A: Here we have to divide two polynomials as shown.

Q: Z4×Z6 has an element of order 24. true or false ?

A:

Q: いーx)dx

A:

Q: 2. (1 + 3/2x − 1)² = 3 + √3/2x − 1

A:

Q: 4 -3 4m n 16) 22 4m n

A:

Q: -96 6 -7 A = -3 d 4A.

A:

Q: (2n)! 323. 2n

A:

Q: 7. (2x + y)³

A:

Contingency Table

A contingency table can be defined as the visual representation of the relationship between two or more categorical variables that can be evaluated and registered. It is a categorical version of the scatterplot, which is used to investigate the linear relationship between two variables. A contingency table is indeed a type of frequency distribution table that displays two variables at the same time.

Binomial Distribution

Binomial is an algebraic expression of the sum or the difference of two terms. Before knowing about binomial distribution, we must know about the binomial theorem.