Need output. #include #include using namespace std; int main(int argc, char const *argv[]) { char arr[12] = "H3ll0\tW0r1d"; for(int i=0;i<12;i++) { cout<<(bool)isprint(arr[i]); } }
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Need answer quickly
Need output.
#include <iostream>
#include <cctype>
using namespace std;
int main(int argc, char const *argv[])
{
char arr[12] = "H3ll0\tW0r1d";
for(int i=0;i<12;i++)
{
cout<<(bool)isprint(arr[i]);
}
}
Step by step
Solved in 2 steps with 2 images
- Questions: There needs to be a dynamic array of Child that opposes with SCALE and is assigned to "familyTree". The createFamilyTree() function needs to be defined. Please see the C++ code.#include #include using namespace std; //function prototypesint countLetters(char*); int countDigits(char*); int countWhiteSpace(char*); int main() { int numLetters, numDigits, numWhiteSpace; char inputString[51]; cout <<"Enter a string of no more than 50 characters: " << endl << endl; cin.getline(inputString,51); numLetters = countLetters(inputString); numDigits = countDigits(inputString); numWhiteSpace = countWhiteSpace(inputString); cout << "The number of letters in the entered string is " << numLetters << endl; cout << "The number of digits in the entered string is " << numDigits << endl; cout << "The number of white spaces in the entered string is " << numWhiteSpace << endl; return 0; } int countLetters(char *strPtr) { int occurs = 0; while(*strPtr != '\0') // loop is executed as long as// the pointer strPtr does not point // to the null character which// marks the end of the string // isalpha determines…#include<iostream>#include<string>#include <cstdlib>#include <ctime>#include<time.h>#include <iomanip>using namespace std; void merge(string a[], string b[], int left, int mid, int right) {int nL = mid - left + 1;int nR = right - mid;string leftA[nL], rightA[nR], leftB[nL], rightB[nR];for(int i = 0; i < nL; i++) {leftA[i] = a[nL+i];leftB[i] = b[nL+i];}for(int i = 0; i < nR; i++) {rightA[i] = a[mid+i+1];rightB[i] = b[mid+i+1];}int i = 0, j = 0, k = left;while(i < nL && j < nR) {if(leftA[i] <= rightA[j]) {a[k] = leftA[i];b[k] = leftB[i];i++;}else {a[k] = rightA[j];b[k] = rightB[j];j++;k++;}}while(i < nL) {a[k] = leftA[i];b[k] = leftB[i];i++;k++;}while(j < nR) {a[k] = rightA[j];b[k] = rightB[j];j++;k++;}} void mergeSort(string a[], string b[], int left, int right) {int mid;if(left < right) {mid = left + (right-1)/2;mergeSort(a,b,left,mid);mergeSort(a,b,mid+1,right);merge(a,b,left,mid,right);}} int menu() {int…
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- demo.cpp #include "Poly.h" #include<iostream> using namespace std; int main() { Poly p1; couble d[3]={1,2,3}: Poly p2(3, d); Poly p3(p2); cout << "Polynomial p1 is: "; p1.display(); cout << "Polynomial p2 is: " << p2 << endl; cout << "Polynomial p3 is: " << p3 << endl; if (p2 == p3) { cout << "p2 and p3 are the same."; } else { cout << "p2 and p3 are different."; } cout << endl; cout << "The coefficient of power 1 of p3 is: " << p2.getCoef(1) << endl; p3.setCoef(1, 99); cout << "p3 after setup is: " << p3 << endl; if (p2 == p3) { cout << "p2 and p3 are the same."; } else { cout << "p2 and p3 are different."; } cout << endl; Poly p4; cout << "Please enter the power and coefficients of Polynomial p4: " << endl; cin >> p4; cout <<…Please Help In JAVA Here is the skeleton of a code for insertion sorting in an imperative language. You have to add right lines of codes for the language you choose (C, C++, C#, JAVA etc,). The following sample is for C++. #include <iostream>#include <array>#include <stdio.h>#include <stdlib.h>#include <ctime>using namespace std; void insertionSort(int A[], int n){for (int i = n-2; i >= 0; i--){ int j; int v = A[i]; for (j = i + 1; j <= n-1; j++) { if (A[j] > v) break; else A[j-1] = A[j]; } A[j-1] = v;}} int *randomArray(int n){srand((unsigned) time(0));int * A = new int [n];for (int i = 0; i < n; i++){ A[i] = rand();}return A;} Sample function calls (call these functions in main driver function):int n = 100000;int * A = randomArray(n);insertionSort(A, n);delete [] A; Note: delete memory of first array before sorting second array. After you modify the code: (1) Generate 100, 000 random numbers and sort them (2) Generate 300000…In C++ Assume that a 5 element array of type string named boroughs has been declared and initialized. Write the code necessary to switch (exchange) the values of the first and last elements of the array.
- #include <iostream> #include <string> #include <cstdlib> using namespace std; template<class T> T func(T a) { cout<<a; return a; } template<class U> void func(U a) { cout<<a; } int main(int argc, char const *argv[]) { int a = 5; int b = func(a); return 0; } Give output for this code.Kindly fix the code:In C programming. How do I find the max and min values of the corressponding columns. #include <stdio.h>#include <math.h>#include <stdlib.h>#define NROWS 5#define NCOLS 5 int main(void){ int i,j, max, min, m, n; float M[NROWS][NCOLS], Mt[NROWS][NCOLS]; char key_hit; //Input the sizes printf("ROW size(1-5) : ");scanf("%d",&m); printf("Column size(1-5): ");scanf("%d",&n); //Size Check while(m>NROWS || n>NCOLS) { printf("Please re-enter the sizes. \n"); printf("Row size(1-5) : ");scanf("%d", &m); printf("Column size(1-5) : ");scanf("%d", &n); } //Input the Matrix Data for(i=0; i<m; i++) for(j=0; j<n; j++) { printf("M[%d][%d] = ", i,j); scanf("%f", &M[i][j]); } //Print the Matrix Data for(i=0; i<m; i++) { for(j=0; j<n; j++) { printf("%1.2f\t", M[i][j]); }…
