Need help with D,E,F please! The mean height of an adult giraffe is 17 feet. Suppose that thedistribution is normally distributed with standard deviation 0.8feet. Let X be the height of a randomly selected adult giraffe.Round all answers to 4 decimal places where possible.a. What is the distribution of X? X - N(b. What is the median giraffe height?ft.c. What is the Z-score for a giraffe that is 19 foot tall?d. What is the probability that a randomly selected giraffe will beshorter than 17.1 feet tall?e. What is the probability that a randomly selected giraffe will bebetween 16.8 and 17.5 feet tall?f. The 70th percentile for the height of giraffes isft.

Name: Need help with D,E,F please! The mean height of an adult giraffe is 17
Uploaded: 2024-03-20T06:38:44.000Z
Channel: Bartleby
Description: Need help with D,E,F please! The mean height of an adult giraffe is 17 feet. Suppose that thedistribution is normally distributed with standard deviation 0.8feet. Let X be the height of a randomly selected adult giraffe.Round all answers to 4 decimal

Given: μ=17 & σ=0.8 Part d: The required probability is P(X≤17.1)= PX-μσ≤17.1-μσ…

Answered: Need help with D,E,F please!

MATLAB: An Introduction with Applications

6th Edition

ISBN:9781119256830

Author:Amos Gilat

Publisher:Amos Gilat

Chapter1: Starting With Matlab

Section: Chapter Questions

Problem 1P

See similar textbooks

Related questions

Concept explainers

Topic Video

Question

Need help with D,E,F please!

The mean height of an adult giraffe is 17 feet. Suppose that the
distribution is normally distributed with standard deviation 0.8
feet. Let X be the height of a randomly selected adult giraffe.
Round all answers to 4 decimal places where possible.
a. What is the distribution of X? X - N(
b. What is the median giraffe height?
ft.
c. What is the Z-score for a giraffe that is 19 foot tall?
d. What is the probability that a randomly selected giraffe will be
shorter than 17.1 feet tall?
e. What is the probability that a randomly selected giraffe will be
between 16.8 and 17.5 feet tall?
f. The 70th percentile for the height of giraffes is
ft.

Expert Solution

Step 1

Given: $μ = 17 & σ = 0.8$

Part d: The required probability is

$P (X \leq 17.1) = P (\frac{X - μ}{σ} \leq \frac{17.1 - μ}{σ}) = P (Z \leq \frac{17.1 - 17}{0.8}) = P (Z \leq 0.13) = 0.448$

Part e: The required probability is

$P (16.8 \leq X \leq 17.5) = P (\frac{17.1 - μ}{σ} \leq \frac{X - μ}{σ} \leq \frac{17.1 - μ}{σ}) = P (\frac{16.8 - 17}{0.8} \leq Z \leq \frac{17.5 - 17}{0.8}) = P (- 0.25 \leq Z \leq 0.63) = P (Z \leq 0.63) - P (Z \leq - 0.25) = 0.7356 - 0.4013 = 0.3343$

Step by step

Solved in 2 steps with 1 images

SEE SOLUTION Check out a sample Q&A here

Knowledge Booster

$Propositional Calculus$

Learn more about

Need a deep-dive on the concept behind this application? Look no further. Learn more about this topic, statistics and related others by exploring similar questions and additional content below.

Similar questions