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Elementary Geometry For College Students, 7e
7th Edition
ISBN:9781337614085
Author:Alexander, Daniel C.; Koeberlein, Geralyn M.
Publisher:Alexander, Daniel C.; Koeberlein, Geralyn M.
ChapterP: Preliminary Concepts
SectionP.CT: Test
Problem 1CT
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In triangle \( \triangle SMD \), point \( B \) is the midpoint of \( SM \), point \( N \) is the midpoint of \( MD \), and point \( T \) is the midpoint of \( DS \).

**Part A**: Find the length of \( SM \).

- **Answer**:

**Part B**: Determine the value of \( x + y + z \).

- **Answer**:

**Part C**: Find the value of \( NT + TB - BN \).

- **Answer**:

### Diagram Explanation

The diagram presents a triangle \( \triangle SMD \) with the following details:

- Line segment \( SM \) is divided by midpoint \( B \). The length of \( SB \) is represented as \( 4x \).
- Line segment \( MD \) is divided by midpoint \( N \). The length \( MN \) is given as \( 102 \).
- Line segment \( DS \) is divided by midpoint \( T \). The length \( DT \) is \( \frac{7}{10}z \).
- Other given lengths:
  - \( MB \) is \( 98.3 \).
  - \( SD \) is \( 123.4 \).
  - \( DN \) is \( \frac{2}{5}y \).

The task is to use these measurements and relationships to solve the given problems in each part.
Transcribed Image Text:In triangle \( \triangle SMD \), point \( B \) is the midpoint of \( SM \), point \( N \) is the midpoint of \( MD \), and point \( T \) is the midpoint of \( DS \). **Part A**: Find the length of \( SM \). - **Answer**: **Part B**: Determine the value of \( x + y + z \). - **Answer**: **Part C**: Find the value of \( NT + TB - BN \). - **Answer**: ### Diagram Explanation The diagram presents a triangle \( \triangle SMD \) with the following details: - Line segment \( SM \) is divided by midpoint \( B \). The length of \( SB \) is represented as \( 4x \). - Line segment \( MD \) is divided by midpoint \( N \). The length \( MN \) is given as \( 102 \). - Line segment \( DS \) is divided by midpoint \( T \). The length \( DT \) is \( \frac{7}{10}z \). - Other given lengths: - \( MB \) is \( 98.3 \). - \( SD \) is \( 123.4 \). - \( DN \) is \( \frac{2}{5}y \). The task is to use these measurements and relationships to solve the given problems in each part.
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