Near the surface of the Earth there is an electric field of about 150 V/m which points downward. Two identical balls with mass m = 0.670 kg are dropped from a height of 2.00 m, but one of the balls is positively charged with q1 = 650 µC, and the second is negatively charged with q, = -650 µC. Use conservation of energy to determine the difference in the speed of the two balls when they hit the ground. (Neglect air resistance.)
Near the surface of the Earth there is an electric field of about 150 V/m which points downward. Two identical balls with mass m = 0.670 kg are dropped from a height of 2.00 m, but one of the balls is positively charged with q1 = 650 µC, and the second is negatively charged with q, = -650 µC. Use conservation of energy to determine the difference in the speed of the two balls when they hit the ground. (Neglect air resistance.)
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![Near the surface of the Earth there is an electric field of
about 150 V/m which points downward. Two identical balls
with mass m = 0.670 kg are dropped from a height of 2.00 m,
but one of the balls is positively charged with q1 = 650 µC,
and the second is negatively charged with q, = -650 µC.
Use conservation of energy to determine the difference in
the speed of the two balls when they hit the ground. (Neglect
air resistance.)](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2F9fd06d49-08c1-4c69-9a5c-c5b264d85373%2F2cc71a40-6839-4599-866c-c0bf03ec60ae%2Ff6hz4r.png&w=3840&q=75)
Transcribed Image Text:Near the surface of the Earth there is an electric field of
about 150 V/m which points downward. Two identical balls
with mass m = 0.670 kg are dropped from a height of 2.00 m,
but one of the balls is positively charged with q1 = 650 µC,
and the second is negatively charged with q, = -650 µC.
Use conservation of energy to determine the difference in
the speed of the two balls when they hit the ground. (Neglect
air resistance.)
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