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ne parallel plate capacitor сарас

ne parallel plate capacitor сарас

Introductory Circuit Analysis (13th Edition)
Introductory Circuit Analysis (13th Edition)
13th Edition
ISBN:9780133923605
Author:Robert L. Boylestad
Publisher:Robert L. Boylestad
Chapter1: Introduction
Section: Chapter Questions
Problem 1P: Visit your local library (at school or home) and describe the extent to which it provides literature...
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In Lab 3, the parallel plate capacitor has a set of thin spacers to prevent the plates from direct contact with each other. Suppose that the thickness of the spacers is 0.8mm. During the experiment, a stack of paper with a total thickness of 4mm is inserted between the plates of the capacitor. (Due to the presence of the thin spacers, the actual separation of the two plates becomes 4.8mm.) One of the plates of the capacitor is charged with -3µC of (negative) charge per square meter area, while the other plate is grounded. Treat the plates as infinitely large. Suppose that the electric susceptibility of air is 0 and that the electric susceptibility of the paper is given as Xe = 0.5. a) Calculate the electric displacement between the plates. b) Calculate the electric field in the air gap that is created by the thin spacers. c) Calculate the electric field inside the paper. d) Calculate the potential difference between the two plates of the capacitor. e) Calculate the capacitance per unit area of this capacitor under this scenario. f) Use da as the thickness of the air gap, dp as the thickness of the paper stack, Xe as the electric susceptibility of the paper. Derive a general expression for the capacitance per unit area of the capacitor when there is both paper and air gap between the plates.
Transcribed Image Text:In Lab 3, the parallel plate capacitor has a set of thin spacers to prevent the plates from direct contact with each other. Suppose that the thickness of the spacers is 0.8mm. During the experiment, a stack of paper with a total thickness of 4mm is inserted between the plates of the capacitor. (Due to the presence of the thin spacers, the actual separation of the two plates becomes 4.8mm.) One of the plates of the capacitor is charged with -3µC of (negative) charge per square meter area, while the other plate is grounded. Treat the plates as infinitely large. Suppose that the electric susceptibility of air is 0 and that the electric susceptibility of the paper is given as Xe = 0.5. a) Calculate the electric displacement between the plates. b) Calculate the electric field in the air gap that is created by the thin spacers. c) Calculate the electric field inside the paper. d) Calculate the potential difference between the two plates of the capacitor. e) Calculate the capacitance per unit area of this capacitor under this scenario. f) Use da as the thickness of the air gap, dp as the thickness of the paper stack, Xe as the electric susceptibility of the paper. Derive a general expression for the capacitance per unit area of the capacitor when there is both paper and air gap between the plates.
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