ne of your classmates is tra ackyard and jumped off her rain. The student weighs 12 ne roof's height is h = 25 ft. vill bottom out (meaning th dequate value of ht?


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The above given question is based upon energy balance of the system at different positions.
So, to obtain the correct solution to the given question, we must balance the energies of the student at point1 (at height h) and point 2(after being hit to the trampoline). It can be clearly seen from the figure that the student possess only potential energy at point 1 and this energy is being absorbed by the trampoline when the student hits it.
So, we just need to calculate the resultant potential energy of the student with respect to trampoline at point 1 and equate it to the elastic energy of the trampoline at point 2 and we will reach to the correct solution.
So, let us begin with our calculation in the next step as give below.
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