Start your discussion at the lowest temperature shown on the graph and discuss the changes as you go up to the top of the graph. Temperature, T0T₁T,0.2NS-x3s-0.40.6(d Mole fraction of B,ХВ0.81Tn H8.0 8.0 A.Q S.O8.0 3.0.0S.Oaro-Figure 5.1 The phase diagram for two partially miscible liquids.E5C.2(b) Refer toto Fig. 5.1 again. Describe wDescribe what will be obserbe observed when a upilmixture of composition x = 0.3 is heated, at each stage giving the number, nicomposition, and relative amounts of the phases present.levE5lic79li(

We are needed to describe the change that will be observed when a mixture of composition χB = 0.3 is heated. Certain pairs of liquids are miscible with each other in limited range of considerations concentrations and are known as partial miscible liquids. From the given phase diagram of the two miscible liquid, it can be stated that B is initially completely soluble in A but as soon as the mole fraction of B increases from 0.3, the two conjugate solution will be formed. These two solutions are : (i) A saturated solution of A in B (ii) A saturated solution of B in A These two solutions are in equilibrium with each other and are known as conjugate solutions. The phase diagram of two partially miscible liquids is given as follows: When a solution having 0.3 mole fraction of B is heated, initially at the lowest temperature, two different phase will be present. These two different phase will be due to the two conjugate solution which exist in equilibrium with each other. The relative amount of these two different layer at any point of time can be calculated by using Lever rule as follows: The relative amount of two layer at point A can be calculated as follows: Relative amount of two layer = abac= 0.83 - 0.30.3-0.2= 0.530.1= 5.3 Hence at point A the solution of B in A will be 5 times the solution of A in B. As the temperature is further raised to T2, the two layers will merge into each other forming a single phase and will exist a single solution at a temperature higher than T2.