nd the equation of the parabola with vertex at (5,-2) and focus at (5,-4). (x – 5)² = 8(y + 2) (x + 5)² = -8(y + 2) (x – 5)² = -8(y – 2) (x - 5)2 = -8(y + 2) %3D
nd the equation of the parabola with vertex at (5,-2) and focus at (5,-4). (x – 5)² = 8(y + 2) (x + 5)² = -8(y + 2) (x – 5)² = -8(y – 2) (x - 5)2 = -8(y + 2) %3D
Calculus: Early Transcendentals
8th Edition
ISBN:9781285741550
Author:James Stewart
Publisher:James Stewart
Chapter1: Functions And Models
Section: Chapter Questions
Problem 1RCC: (a) What is a function? What are its domain and range? (b) What is the graph of a function? (c) How...
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![5. Find the equation of the parabola with vertex at (5,-2) and focus at (5,-4).
а. (х — 5)2 %3D 8(у + 2)
b. (x + 5)² = -8(y+ 2)
с. (х — 5)? %3D —-8(у — 2)
d. (x – 5)? = -8(y + 2)](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2F77fc5422-0f9d-4beb-93bc-cd5ea00fa352%2Fa7d920b8-7e5d-4b1e-95b1-ad5d9885cd77%2Fdy70md_processed.png&w=3840&q=75)
Transcribed Image Text:5. Find the equation of the parabola with vertex at (5,-2) and focus at (5,-4).
а. (х — 5)2 %3D 8(у + 2)
b. (x + 5)² = -8(y+ 2)
с. (х — 5)? %3D —-8(у — 2)
d. (x – 5)? = -8(y + 2)
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