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nd diameter

nd diameter

Structural Analysis
Structural Analysis
6th Edition
ISBN:9781337630931
Author:KASSIMALI, Aslam.
Publisher:KASSIMALI, Aslam.
Chapter2: Loads On Structures
Section: Chapter Questions
Problem 1P
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How do I find the specimen’s final length and diameter
tab ! 1 omework No. 2 Q 2 IET 131 Construction Materials W # 3 E 4 R % 5 I Name 6 & 7 Joshua Harper Date 9/4/22 8 9 A cylinder with a 6-in diameter and 12-in length is put under a compressive load of 150 kips. The (10 Points) modulus of elasticity for this specimen is 8000 ksi and Poisson's ratio is 0.35. a) Calculate the specimen's final length (in) b) Calculate the specimen's final diameter (in) Note: Because the specimen is under a compressive load, its final length, L, will decrease and its final diameter, De will increase. Sokips 28.27 ylindrical rod with a radius of 0.3-in and a length of 15-in is subjected to a tensile load. is to experience neither plastic deformation nor an elongation, & of more than 0. which of the four metals or alloys listed below are p 7000 IL
Transcribed Image Text:tab ! 1 omework No. 2 Q 2 IET 131 Construction Materials W # 3 E 4 R % 5 I Name 6 & 7 Joshua Harper Date 9/4/22 8 9 A cylinder with a 6-in diameter and 12-in length is put under a compressive load of 150 kips. The (10 Points) modulus of elasticity for this specimen is 8000 ksi and Poisson's ratio is 0.35. a) Calculate the specimen's final length (in) b) Calculate the specimen's final diameter (in) Note: Because the specimen is under a compressive load, its final length, L, will decrease and its final diameter, De will increase. Sokips 28.27 ylindrical rod with a radius of 0.3-in and a length of 15-in is subjected to a tensile load. is to experience neither plastic deformation nor an elongation, & of more than 0. which of the four metals or alloys listed below are p 7000 IL
Expert Solution
Step 1

given data,

length, l = 12 in

diameter, d = 6 in

compressive load, P = 150kips

modulus of elasticity, E = 8000ksi

Poisson's ratio, v = 0.35

σ = 150/ (0.785 * 62) = 5.308 Ksi

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