How do I find the specimen’s final length and diameter tab!1omework No. 2Q2IET 131 Construction MaterialsW#3E4R%5IName6&7Joshua HarperDate 9/4/2289A cylinder with a 6-in diameter and 12-in length is put under a compressive load of 150 kips. The(10 Points)modulus of elasticity for this specimen is 8000 ksi and Poisson's ratio is 0.35.a) Calculate the specimen's final length (in)b) Calculate the specimen's final diameter (in)Note: Because the specimen is under a compressive load, its final length, L, will decrease and itsfinal diameter, De will increase.Sokips28.27ylindrical rod with a radius of 0.3-in and a length of 15-in is subjected to a tensile load.is to experience neither plastic deformation nor an elongation, & of more than 0.which of the four metals or alloys listed below are p7000 IL

Answered: nd diameter

Engineering

Civil Engineering

nd diameter

Structural Analysis

6th Edition

ISBN:9781337630931

Author:KASSIMALI, Aslam.

Publisher:KASSIMALI, Aslam.

Chapter2: Loads On Structures

Section: Chapter Questions

Problem 1P

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Question

How do I find the specimen’s final length and diameter

tab
!
1
omework No. 2
Q
2
IET 131 Construction Materials
W
#
3
E
4
R
%
5
I
Name
6
&
7
Joshua Harper
Date 9/4/22
8
9
A cylinder with a 6-in diameter and 12-in length is put under a compressive load of 150 kips. The
(10 Points)
modulus of elasticity for this specimen is 8000 ksi and Poisson's ratio is 0.35.
a) Calculate the specimen's final length (in)
b) Calculate the specimen's final diameter (in)
Note: Because the specimen is under a compressive load, its final length, L, will decrease and its
final diameter, De will increase.
Sokips
28.27
ylindrical rod with a radius of 0.3-in and a length of 15-in is subjected to a tensile load.
is to experience neither plastic deformation nor an elongation, & of more than 0.
which of the four metals or alloys listed below are p
7000 IL

Expert Solution

Step 1

given data,

length, l = 12 in

diameter, d = 6 in

compressive load, P = 150kips

modulus of elasticity, E = 8000ksi

Poisson's ratio, v = 0.35

σ = 150/ (0.785 * 6²) = 5.308 Ksi

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