nber 37. It flx) = x? + 10 sin x, show that there is C such that fle) = 1000. %3D a num

Calculus: Early Transcendentals
8th Edition
ISBN:9781285741550
Author:James Stewart
Publisher:James Stewart
Chapter1: Functions And Models
Section: Chapter Questions
Problem 1RCC: (a) What is a function? What are its domain and range? (b) What is the graph of a function? (c) How...
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Hi. I had a question regarding the values used in this problem. On the bartleby textbook, the values 31 and 32 were used for this problem. However, is this problem limited to those two specific valhes?
< Chapter 2.5, Problen
Theorem used: The Intermediate value Theorem
Suppose that if fis continuous on the closed interval [a, b] and let
number between f (a) and f (b), where f (a) + f (b). Then,
there exists a number cin (a, b) such that f (c) = N.
be
any
Proof:
Consider the function f (x) = x² + 10 sin x.
%3D
Here, f (x) is a combination of polynomial and trigonometric
function. Both are continuous everywhere. Therefore, f (x) also
continuous on R.
Without loss of generality, take the subinterval [31, 32] C R.
Take a = 31, b = 32 andN = 1000.
Substitute 31 for x in f (x),
f (31) = (31) + 10 sin (31)
961 + 10 (-0.40404)
= 961 – 4.0404
2 957
This implies that, f (31) = 957 < 1000.
Substitute 32 for x in f (x),
立
Transcribed Image Text:< Chapter 2.5, Problen Theorem used: The Intermediate value Theorem Suppose that if fis continuous on the closed interval [a, b] and let number between f (a) and f (b), where f (a) + f (b). Then, there exists a number cin (a, b) such that f (c) = N. be any Proof: Consider the function f (x) = x² + 10 sin x. %3D Here, f (x) is a combination of polynomial and trigonometric function. Both are continuous everywhere. Therefore, f (x) also continuous on R. Without loss of generality, take the subinterval [31, 32] C R. Take a = 31, b = 32 andN = 1000. Substitute 31 for x in f (x), f (31) = (31) + 10 sin (31) 961 + 10 (-0.40404) = 961 – 4.0404 2 957 This implies that, f (31) = 957 < 1000. Substitute 32 for x in f (x), 立
37. I t flx) = x? + 10 sinx, show that there is a
C such that flc) = 1000.
%3D
number
to
16)<1000
Transcribed Image Text:37. I t flx) = x? + 10 sinx, show that there is a C such that flc) = 1000. %3D number to 16)<1000
Expert Solution
Step 1

Short Answer: Yes the values 31 and 32 are specific to this problem only.

Explanation: We are given the function x2+10sinx, we need to show that there exist a number c such that f(c)=1000.

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