NB: For figure check the attached suppleemnt. A 75.0 N force is applied on a mass of 11.5 kg at an angle of 30.0 degree with the horizontal. Given coefficient of friction between the surfaces is 0.18 Calculate the following quantities [a] Normal force N [b] Frictional force [c] Net force along x direction [d] Acceleration [e] Given initial velocity zero, what distance the object travels in 4.0 s
NB: For figure check the attached suppleemnt. A 75.0 N force is applied on a mass of 11.5 kg at an angle of 30.0 degree with the horizontal. Given coefficient of friction between the surfaces is 0.18 Calculate the following quantities [a] Normal force N [b] Frictional force [c] Net force along x direction [d] Acceleration [e] Given initial velocity zero, what distance the object travels in 4.0 s
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PLEASE ANSWER PART D AND E
![NB: For figure check the attached suppleemnt.
A 75.0 N force is applied on a mass of 11.5 kg at an angle of 30.0 degree with the horizontal. Given coefficient of friction between the surfaces is 0.18
Calculate the following quantities
[a] Normal force N
[b] Frictional force
[c] Net force along x direction
[d] Acceleration
[e] Given initial velocity zero, what distance the object travels in 4.0 s](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2Ff76b078b-7457-467f-be00-996eb7c0bbaa%2F40c3d485-a829-4579-a5b3-fe15f6a5fa35%2Fh4mqouf_processed.png&w=3840&q=75)
Transcribed Image Text:NB: For figure check the attached suppleemnt.
A 75.0 N force is applied on a mass of 11.5 kg at an angle of 30.0 degree with the horizontal. Given coefficient of friction between the surfaces is 0.18
Calculate the following quantities
[a] Normal force N
[b] Frictional force
[c] Net force along x direction
[d] Acceleration
[e] Given initial velocity zero, what distance the object travels in 4.0 s
![[Q05] A 75.0 N force is applied on a mass of 11.5 kg at an angle of 30.0 degree with the
horizontal. Given coefficient of friction between the surfaces is 0.18
30°
F
= 75 N
app](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2Ff76b078b-7457-467f-be00-996eb7c0bbaa%2F40c3d485-a829-4579-a5b3-fe15f6a5fa35%2Foaa4nx4_processed.png&w=3840&q=75)
Transcribed Image Text:[Q05] A 75.0 N force is applied on a mass of 11.5 kg at an angle of 30.0 degree with the
horizontal. Given coefficient of friction between the surfaces is 0.18
30°
F
= 75 N
app
Expert Solution
![](/static/compass_v2/shared-icons/check-mark.png)
Step 1
Given value---
- applied force = 75 N.
- Mass = 11.5 kg.
- coefficient of friction force = 0.18 .
- angle = 30 degree.
We have to find---
- acceleration?
- Given initial velocity zero, what distance the object travels in 4.0 s
Step by step
Solved in 2 steps with 1 images
![Blurred answer](/static/compass_v2/solution-images/blurred-answer.jpg)
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