Nationally, patients who go to the emergency room wait an average of 6 hours to be admitted into the hospital. Do patients at rural hospitals have a different waiting time? The 14 randomly selected patients who went to the emergency room at rural hospitals waited an average of 5.1 hours to be admitted into the hospital. The standard deviation for these 14 patients was 1.4 hours. What can be concluded at the αα = 0.01 level of significance level of significance? c. The test statistic t = ? (please show your answer to 3 decimal places.) d. The p-value = ? (Please show your
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Nationally, patients who go to the emergency room wait an average of 6 hours to be admitted into the hospital. Do patients at rural hospitals have a different waiting time? The 14 randomly selected patients who went to the emergency room at rural hospitals waited an average of 5.1 hours to be admitted into the hospital. The standard deviation for these 14 patients was 1.4 hours. What can be concluded at the αα = 0.01 level of significance level of significance?
c. The test statistic t = ? (please show your answer to 3 decimal places.)
d. The p-value = ? (Please show your answer to 4 decimal places.)
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- A kilo restaurant implemented a change in the composition and presentation of its dishes. We want to assess whether the average weight of meals served is greater after the changes, compared to the previous average, which was 640. For this purpose, the weights of dishes from a random sample of 10 customers were taken. The average weight of dishes in the sample was 656 and the variance 144. Use a statistical test for the evaluation. Adopt a significance level of 10%. a. What is the distribution of the test statistic? b. What kind of alternative hypothesis? c. What is the test's critical value (the value that defines the critical region), on the scale of the test statistic? (If the test is bilateral, enter only one of the values.)Kenneth, a competitor in cup stacking, claims that his average stacking time is 8.2 seconds. During a practice session, Kenneth has a sample stacking time mean of 7.8 seconds based on 11 trials. At the 4% significance level, does the data provide sufficient evidence to conclude that Kenneth's mean stacking time is less than 8.2 seconds? Accept or reject the hypothesis given the sample data below. H0:μ=8.2 seconds; Ha:μ<8.2 seconds α=0.04 (significance level) z0=−1.75 p=0.0401 Select the correct answer below: a. Do not reject the null hypothesis because the p-value 0.0401 is greater than the significance level α=0.04. b. Reject the null hypothesis because the p-value 0.0401 is greater than the significance level α=0.04. c. Reject the null hypothesis because the value of z is negative. d. Reject the null hypothesis because |−1.75|>0.04. e. Do not reject the null hypothesis because |−1.75|>0.04.A random sample of 49 cans of soda is obtained and the contents are measured. The sample mean is 12.01 oz and the standard deviation is 0.13 oz. Test the claim that the contents of all such cans have a mean different from 12.00 oz, as indicated by the label. Use a 0.05 significance level. Find the Z score And the P value. Do you reject the hypothesis?
- Listed below are the lead concentrations (in ug/g) measured in different Ayurveda medicines. Ayurveda is a traditional medical system commonly used in India. The lead concentrations listed here are from medicines manufactured in the United States. Assume that a simple random sample has been selected. Use a 0.01 significance level to test the claim that the mean lead concentration for all such medicines is less than 14.0 µg /g. 2.96 6.45 5.99 5.51 20.53 7.45 11.97 20.46 11.52 17.54 D Identify the null and alternative hypotheses. Ho: H1: (Type integers or decimals. Do not round.) Identify the test statistic. (Round to two decimal places as needed.) Identify the P-value. (Round to three decimal places as needed.) State the conclusion about the null hypothesis, as well as the final conclusion that addresses the original claim. V the null hypothesis. There sufficient evidence at the 0.01 significance level to V the claim that the mean lead concentration for all Ayurveda medicines…Listed below are the lead concentrations (in µg/g) measured in different Ayurveda medicines. Ayurveda is a traditional medical system commonly used in India. The lead concentrations listed here are from medicines manufactured in the United States. Assume that a simple random sample has been selected. Use a 0.05 significance level to test the claim that the mean lead concentration for all such medicines is less than 14.0 µg/g. 5.98 5.50 20.54 3.03 6.46 Identify the null and alternative hypotheses. Ho: H 14 H₁: μ 14 (Type integers or decimals. Do not round.) Identify the test statistic. = (Round to two decimal places as needed.) 7.45 12.01 20.47 11.48 17.53 D S Vi I. (1,0) MoreA study was done using a treatment group and a placebo group. The results are shown in the table. Assume that the two samples are independent simple random samples selected from normally distributed populations, and do not assume that the population standard deviations are equal. Complete parts (a) and (b) below. Use a 0.10 significance level for both parts. a. Test the claim that the two samples are from populations with the same mean. What are the null and alternative hypotheses? OA. Ho: H₁ H₂ H₁: Hq ZH₂ OC. Ho: H₁ H₂ H₁: Hy > H₂ The test statistic, t, is. (Round to two decimal places as needed.) (Round to three decimal places as needed.) The P-value is State the conclusion for the test. C... OB. Ho: H₁ H₂ H₁: Hy #H₂ OD. Ho: Hg #U2 H₁: HyListed below are the lead concentrations (in µg/g) measured in different Ayurveda medicines. Ayurveda is a traditional medical system commonly used in India. The lead concentrations listed here are from medicines manufactured in the United States. Assume that a simple random sample has been selected. Use a 0.01 significance level to test the claim that the mean lead concentration for all such medicines is less than 14.0 μg/g. 2.95 6.46 6.00 5.46 20.49 7.51 12.02 20.45 11.50 17.54 Identify the null and alternative hypotheses. Ho H₁: (Type integers or decimals. Do not round.)The average retirement age in America is 64 years old. Do small business owners retire at a younger average age? The data below shows the results of a survey of small business owners who have recently retired. Assume that the distribution of the population is normal. 63, 54, 69, 69, 53, 53, 71, 51, 61, 60, 69, 54 What can be concluded at the the a = 0.01 level of significance level of significance? a. For this study, we should use t-test for a population mean b. The null and alternative hypotheses would be: Но: μν H1: c. The test statistic t (please show your answer to 3 decimal places.) d. The p-value = (Please show your answer to 4 decimal places.) IIA study was done using a treatment group and a placebo group. The results are shown in the table. Assume that the two samples are independent simple random samples selected from normally distributed populations, and do not assume that the population standard deviations are equal. Complete parts (a) and (b) below. Use a 0.01 significance level for both parts. a. Test the claim that the two samples are from populations with the same mean. What are the null and alternative hypotheses? OA. Ho H1 H2 H₁: H1 H2 The test statistic, t, is -1.55. (Round to two decimal places as needed.) The P-value is (Round to three decimal places as needed.) OB. Ho: H1 H2 H₁₁₂ D. Ho: H1 H2 H₁: H1 H2 Treatment Placebo μ H₁ H2 n 25 40 X 2.38 2.65 S 0.53 0.87A study was done using a treatment group and a placebo group. The results are shown in the table. Assume that the two samples are independent simple random samples selected from normally distributed populations, and do not assume that the population standard deviations are equal. Complete parts (a) and (b) below. Use a 0.01 significance level for both parts. a. Test the claim that the two samples are from populations with the same mean. What are the null and alternative hypotheses? OA. Ho: H₁ H₂ H₁: H₁ H₂ OC. Ho: H₁ H¹/₂ H₁: H₁50 smokers were questioned about the number of hours they sleep each day. We want to test the hypothesis that the smokers need less sleep than the general public which needs an average of 7.7 hours of sleep. We follow the steps below. Compute a rejection region for a significance level of .05. A. If the sample mean is 7.5 and the standard deviation is .5, what can you conclude?In one study of smokers who tried to quit smoking with nicotine path therapy,38 were smoking one year after the treatment, and 32 were not smoking one year after the treatment. Use a 0.10 significance level to test the claim that among smokers who try to quit with nicotine patch therapy, the majority are smoking a year after the treatment. d. Calculate the test statistic z. Which of these options is closest to z? A. negative 2.02 B. 0.72 C. negative 0.25 D. 2.59 e. Calculate the P-value. Which of these options is closest to the P-value? A. 0.2358 B. 0.2164 C. 0.3359 D. 0.2271 f. State the technical conclusion A. Reject Upper H 0 B. Do not reject Upper H 0 g. State the final conclusion A. There is sufficient evidence to warrant rejection of the claim. B. There is not sufficient evidence to warrant rejection of the claim.…SEE MORE QUESTIONSRecommended textbooks for youMATLAB: An Introduction with ApplicationsStatisticsISBN:9781119256830Author:Amos GilatPublisher:John Wiley & Sons IncProbability and Statistics for Engineering and th…StatisticsISBN:9781305251809Author:Jay L. 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