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? NaOH t-BUOK (c) (d)

? NaOH t-BUOK (c) (d)

Chemistry
Chemistry
10th Edition
ISBN:9781305957404
Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Chapter1: Chemical Foundations
Section: Chapter Questions
Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...
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### Reaction Schemes: Understanding Reactants and Conditions **Scheme (c):** - **Reactant:** The structure shown is 2-iodopentane. This organic compound features an iodine (I) substituent on the second carbon of a pentane chain. - **Reagent:** NaOH (sodium hydroxide), a strong base. - **Reaction:** The use of NaOH typically suggests a potential substitution or elimination reaction, possibly leading to the formation of an alcohol or an alkene. - **Outcome:** Indicated by the question mark, prompting exploration into what product(s) might form via these typical reactions. **Scheme (d):** - **Reactant:** Similar to scheme (c), this structure is also 2-iodopentane. - **Reagent:** t-BuOK (potassium tert-butoxide), known for being a bulky, strong base. - **Reaction:** The presence of a bulky base like t-BuOK favors elimination reactions, often leading to the formation of an alkene with the least sterically hindered configuration. - **Outcome:** Represented by the question mark, this suggests predicting the possible alkenes based on the application of Zaitsev’s or Hofmann’s rules, depending on sterics and regioselectivity. These schemes provide opportunities to explore principles of organic chemistry, including substitution vs. elimination reactions and the influence of different bases on reaction pathways.
Transcribed Image Text:### Reaction Schemes: Understanding Reactants and Conditions **Scheme (c):** - **Reactant:** The structure shown is 2-iodopentane. This organic compound features an iodine (I) substituent on the second carbon of a pentane chain. - **Reagent:** NaOH (sodium hydroxide), a strong base. - **Reaction:** The use of NaOH typically suggests a potential substitution or elimination reaction, possibly leading to the formation of an alcohol or an alkene. - **Outcome:** Indicated by the question mark, prompting exploration into what product(s) might form via these typical reactions. **Scheme (d):** - **Reactant:** Similar to scheme (c), this structure is also 2-iodopentane. - **Reagent:** t-BuOK (potassium tert-butoxide), known for being a bulky, strong base. - **Reaction:** The presence of a bulky base like t-BuOK favors elimination reactions, often leading to the formation of an alkene with the least sterically hindered configuration. - **Outcome:** Represented by the question mark, this suggests predicting the possible alkenes based on the application of Zaitsev’s or Hofmann’s rules, depending on sterics and regioselectivity. These schemes provide opportunities to explore principles of organic chemistry, including substitution vs. elimination reactions and the influence of different bases on reaction pathways.
1. Draw the acceptable major product for the following reaction.
Transcribed Image Text:1. Draw the acceptable major product for the following reaction.
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