nan (x - 3)n-1 + x Σ an (ax - 3)* = 0, + n=0 then the recurrence relation can be written as Q6. If Σ n=1 (a) αι = -αρ, (b) αι = 3ao, (c) a1 = - 3ao, (d) a1 = do , (e) a1 = =do , – - (n + 1)an+1 – an−1 + 3an = 0, (n+1)an+1 + an−1 + an = 0, ηΣ1 n>1 – (n+1)an+1 + an−1 + 3an = 0, n>1 (n + 2)an+2 + an−1 + an = 0, (n + 2)an+2 + an−1 + an=0, – η>1 n>1

Q: Suppose that {an} is defined recursively by: an = (an-1)² - 1 and that ao = 2. Find a2 and az.

A:

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A:

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A:

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A:

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A:

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Q: 11 (d) 12/13 + (1 1/12 - 11/1/1)

A: