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nan (x - 3)n-1 + x Σ an (ax - 3)* = 0, + n=0 then the recurrence relation can be written as Q6. If Σ n=1 (a) αι = -αρ, (b) αι = 3ao, (c) a1 = - 3ao, (d) a1 = do , (e) a1 = =do , – - (n + 1)an+1 – an−1 + 3an = 0, (n+1)an+1 + an−1 + an = 0, ηΣ1 n>1 – (n+1)an+1 + an−1 + 3an = 0, n>1 (n + 2)an+2 + an−1 + an = 0, (n + 2)an+2 + an−1 + an=0, – η>1 n>1

nan (x - 3)n-1 + x Σ an (ax - 3)* = 0, + n=0 then the recurrence relation can be written as Q6. If Σ n=1 (a) αι = -αρ, (b) αι = 3ao, (c) a1 = - 3ao, (d) a1 = do , (e) a1 = =do , – - (n + 1)an+1 – an−1 + 3an = 0, (n+1)an+1 + an−1 + an = 0, ηΣ1 n>1 – (n+1)an+1 + an−1 + 3an = 0, n>1 (n + 2)an+2 + an−1 + an = 0, (n + 2)an+2 + an−1 + an=0, – η>1 n>1

Advanced Engineering Mathematics
Advanced Engineering Mathematics
10th Edition
ISBN:9780470458365
Author:Erwin Kreyszig
Publisher:Erwin Kreyszig
Chapter2: Second-order Linear Odes
Section: Chapter Questions
Problem 1RQ
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nan (a – 3)n-1 + x Σ an (x - 3)" = 0, - n=0 then the recurrence relation can be written as (n + 1)an+1 – an−1 + 3an = 0, (n + 1)an+1 + an−1 + an=0, – (n+1)an+1 + an−1 + 3an = 0, η>1 (n + 2)an+2 + an−1 + an = 0, (n + 2)an+2 + an−1 + an = 0, - Q6. 11 Σ n=1 = (a) αι = =do, (b) αι = 3a0 , (c) a1 = - –3ao, (d) a1 = do , (e) a1 = =do , n21 n>1 η21 η>1
Transcribed Image Text:nan (a – 3)n-1 + x Σ an (x - 3)" = 0, - n=0 then the recurrence relation can be written as (n + 1)an+1 – an−1 + 3an = 0, (n + 1)an+1 + an−1 + an=0, – (n+1)an+1 + an−1 + 3an = 0, η>1 (n + 2)an+2 + an−1 + an = 0, (n + 2)an+2 + an−1 + an = 0, - Q6. 11 Σ n=1 = (a) αι = =do, (b) αι = 3a0 , (c) a1 = - –3ao, (d) a1 = do , (e) a1 = =do , n21 n>1 η21 η>1
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