NAME: DATE: QUESTION 5 (5 pt): What is the output? #include void swap (int a, int b) { int tmp = b; b a; = tmp; return; S.8. a } void swap2 (int &a, int &b) { int tmp b; b3D а; tmp; return; a } int main() { int x{100}, y{25}; Swap(x,y)i std::cout<< "x -" < x << ", y=" << y << std:: endl; x-100, y-25 ; swap2 (x,y); std::cout<< "x -" << x << ", y=" << y << std::endl; } end? I1 1 QUESTION 6 (5 pt): What is the output? #include void mystery ( int x[ ] , int n) { int temp; for (int i = 0; i < n / 2 - 1; i++) { temp *[i] *[n - i - 1] = temp; } } int main( f *[i]; X[n - i - 1] ; 11 00 Tay
NAME: DATE: QUESTION 5 (5 pt): What is the output? #include void swap (int a, int b) { int tmp = b; b a; = tmp; return; S.8. a } void swap2 (int &a, int &b) { int tmp b; b3D а; tmp; return; a } int main() { int x{100}, y{25}; Swap(x,y)i std::cout<< "x -" < x << ", y=" << y << std:: endl; x-100, y-25 ; swap2 (x,y); std::cout<< "x -" << x << ", y=" << y << std::endl; } end? I1 1 QUESTION 6 (5 pt): What is the output? #include void mystery ( int x[ ] , int n) { int temp; for (int i = 0; i < n / 2 - 1; i++) { temp *[i] *[n - i - 1] = temp; } } int main( f *[i]; X[n - i - 1] ; 11 00 Tay
Database System Concepts
7th Edition
ISBN:9780078022159
Author:Abraham Silberschatz Professor, Henry F. Korth, S. Sudarshan
Publisher:Abraham Silberschatz Professor, Henry F. Korth, S. Sudarshan
Chapter1: Introduction
Section: Chapter Questions
Problem 1PE
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