Name: (11) The supply voltage VCC equals 9V. The base resistor Rais 42. Take 0.6V for the knee voltage of the base-emitter diode. Draw the load line for a short-circuit current of 15mA (a) What is the value of the collector resistor RC in that case? (b) What is then the voltage Va across the transistor? (c) What is then the current le through the transistor? RB m VCC 9.0V RC lc (mA) 15 Ō 10 Student nr: saturation region 5 Answers: (a) RC- (b) Va= (c) Ic= active region cutoff region 10 15 VCE (V) {npn} 20 L₂=0.4 mA 1₂=0.3 mA IB=0.2 mA Ig=0.1mA Ig=0 mA
Name: (11) The supply voltage VCC equals 9V. The base resistor Rais 42. Take 0.6V for the knee voltage of the base-emitter diode. Draw the load line for a short-circuit current of 15mA (a) What is the value of the collector resistor RC in that case? (b) What is then the voltage Va across the transistor? (c) What is then the current le through the transistor? RB m VCC 9.0V RC lc (mA) 15 Ō 10 Student nr: saturation region 5 Answers: (a) RC- (b) Va= (c) Ic= active region cutoff region 10 15 VCE (V) {npn} 20 L₂=0.4 mA 1₂=0.3 mA IB=0.2 mA Ig=0.1mA Ig=0 mA
Introductory Circuit Analysis (13th Edition)
13th Edition
ISBN:9780133923605
Author:Robert L. Boylestad
Publisher:Robert L. Boylestad
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Question
![Name:
(11) The supply voltage VCC equals 9V. The base resistor RB is 42.
Take 0.6V for the knee voltage of the base-emitter diode. Draw the
load line for a short-circuit current of 15mA
(a) What is the value of the collector resistor RC in that case?
(b) What is then the voltage Va across the transistor?
(c) What is then the current le through the transistor?
RB
www
VCC
9.0V
RC
Ic (mA)
15
D
10
Student nr.
saturation region
5
Answers:
(a) RC-
(b) Va
(c) Ic=
active region
(12) Same circuit and transistor as above, but now with a short-
scircuit current of 5 mA. Draw the new load line. (a) What is the
value of the collector resistor RC in that case? (b) What is then the
voltage Vc across the transistor? (c) What is then the current Ic
through the transistor?
cutoff region
10
15
VCE (V) {npn}
20
Answers:
(a) RC =
(b) VCE=
(c) Ic=
L₂=0.4 mA
1₁-0.3 mA
IB=0.2 mA
Ig=0.1mA
Ig=0 mA](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2Ffc9db276-925f-4220-a7f3-e3f9d551eab2%2F00f1e229-e023-4bdc-91cf-11b55f5b9f42%2F6m4kebo_processed.jpeg&w=3840&q=75)
Transcribed Image Text:Name:
(11) The supply voltage VCC equals 9V. The base resistor RB is 42.
Take 0.6V for the knee voltage of the base-emitter diode. Draw the
load line for a short-circuit current of 15mA
(a) What is the value of the collector resistor RC in that case?
(b) What is then the voltage Va across the transistor?
(c) What is then the current le through the transistor?
RB
www
VCC
9.0V
RC
Ic (mA)
15
D
10
Student nr.
saturation region
5
Answers:
(a) RC-
(b) Va
(c) Ic=
active region
(12) Same circuit and transistor as above, but now with a short-
scircuit current of 5 mA. Draw the new load line. (a) What is the
value of the collector resistor RC in that case? (b) What is then the
voltage Vc across the transistor? (c) What is then the current Ic
through the transistor?
cutoff region
10
15
VCE (V) {npn}
20
Answers:
(a) RC =
(b) VCE=
(c) Ic=
L₂=0.4 mA
1₁-0.3 mA
IB=0.2 mA
Ig=0.1mA
Ig=0 mA
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