NA+Cl2->NaCl is the balanced reaction for the formation of table salt. Given 20 grams of Na and 10 grams of Cl2, which reactant is in excess? How much NaCl should be produced from these amounts of the two reactants

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2 NA+Cl2->NaCl is the balanced reaction for the formation of table salt. Given 20 grams of Na and 10 grams of Cl2, which reactant is in excess? How much NaCl should be produced from these amounts of the two reactants? If you could do it like how I’m being taught in class in this separate problem it would be much appreciated and would help me understand better
Answer:
107.8 g Ag
1 mol Ag
1 mol Cu
2 mol Ag
67.9 g Ag
%3D
20 g Cu x
1 mol Cu
63.5 g Cu
107.8 g Ag
X-
1 mol Ag
1 mol AGNO3
2 mol Ag
X-
2 mol AGNO3
= 12.7 g Ag
20 g AgNO3 x
169.8 g AGNO3
The silver nitrate is the limiting reagent since it will only produce 12.7 g of Ag.
Now, you only weighed out 5 grams of silver after your experiment, but, theoretically, yo
below to calculate the percent yield.
ActualYield
5 a
P Type here to search
amazon
Cocala
F6
F7
F8
OD
A
2
3
W
Transcribed Image Text:Answer: 107.8 g Ag 1 mol Ag 1 mol Cu 2 mol Ag 67.9 g Ag %3D 20 g Cu x 1 mol Cu 63.5 g Cu 107.8 g Ag X- 1 mol Ag 1 mol AGNO3 2 mol Ag X- 2 mol AGNO3 = 12.7 g Ag 20 g AgNO3 x 169.8 g AGNO3 The silver nitrate is the limiting reagent since it will only produce 12.7 g of Ag. Now, you only weighed out 5 grams of silver after your experiment, but, theoretically, yo below to calculate the percent yield. ActualYield 5 a P Type here to search amazon Cocala F6 F7 F8 OD A 2 3 W
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