Na AIF, can be made by the reaction below: Al,O3 () + 6 NaOH ) + 12HF → 2 Na AIF +9 H,0 (I) In an experiment; 6.55 g Al,0, and excess HF were dissolved in 1.75 L of 0.15 M NaOH. If 20 g Na AIF was obtained,

Na AIF, can be made by the reaction below: Al,O3 () + 6 NaOH ) + 12HF → 2 Na AIF +9 H,0 (I) In an experiment; 6.55 g Al,0, and excess HF were dissolved in 1.75 L of 0.15 M NaOH. If 20 g Na AIF was obtained,

Chemistry

10th Edition

ISBN:9781305957404

Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste

Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste

Chapter1: Chemical Foundations

Section: Chapter Questions

Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...

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Question

What is the percentage yield of this experiment ?

Na AIF, can be made by the reaction below:
Al,O3 () + 6 NaOH ) + 12HF → 2 Na AIF +9 H,0 (I)
In an experiment; 6.55 g Al,0, and excess HF were dissolved in 1.75 L of 0.15 M NaOH.
If 20 g Na AIF was obtained,

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