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n7 3000 i n6 n5 n1 n2 n3 Reactor Condenser CO + H2 = CH3OH 1000 0.3 0.6 0.1 n4

n7 3000 i n6 n5 n1 n2 n3 Reactor Condenser CO + H2 = CH3OH 1000 0.3 0.6 0.1 n4

Introduction to Chemical Engineering Thermodynamics
Introduction to Chemical Engineering Thermodynamics
8th Edition
ISBN:9781259696527
Author:J.M. Smith Termodinamica en ingenieria quimica, Hendrick C Van Ness, Michael Abbott, Mark Swihart
Publisher:J.M. Smith Termodinamica en ingenieria quimica, Hendrick C Van Ness, Michael Abbott, Mark Swihart
Chapter1: Introduction
Section: Chapter Questions
Problem 1.1P
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i just want to ask why n1 and n1 be taken to calculate overall masa balance?
E Merge & Center 9. Conditional Format as Cell Table Styles Alignment 00 .0 Formatting Insert Delete Format 7Fill Sort & Find & Filter Select Number IN Clear Styles Cells Editing F H s only CO,H2 and N2 mol/hr is used and rding to the P- le to fresh feed ratio n the recycle stream Stream number 2 4 Molar flow rate (kmol/d) 1000 4000 3600 200 3400 400 3000 CO 0.3 0.26 0.24 0.25 0.5 0.25 0.25 0.25 H2 0.6 0.53 0.47 0.24 0.06 0.5 0.5 N2 CH3OH 0.1 0.21 0.25 0.25 1 Step 1 Overall mass balance To find the extent of reaction, all this 3 equation is needed let ysco = 0.75- y6H, Component mass balance find Stream number 3 = 300 - 400y6co 3 (600 - 400y6H)/2 1 1 molar flow rate 2 (kmol/d) 1000 400 equate 1 and 2 300 - 400y6co= (600 - 400y6H)/2 y1, N2 (n1) = n6(0.25) Yoco (n6) = 0.3(1000) – 5 Y6H2 (n6) = 0.6(1000) – 25 1 = y6co + Y6H2 + 0.25 N2 0.1 0.25 CO 0.3 0.25 subsutitute y6co and solved for y6H 300 - 400(0.75 - y6H) = (600 - 400Y6H)/2 H2 0.6 0.5 Y6H = 0.50 solved Y6co = 0.75 - y6H = 0.25 3619
Transcribed Image Text:E Merge & Center 9. Conditional Format as Cell Table Styles Alignment 00 .0 Formatting Insert Delete Format 7Fill Sort & Find & Filter Select Number IN Clear Styles Cells Editing F H s only CO,H2 and N2 mol/hr is used and rding to the P- le to fresh feed ratio n the recycle stream Stream number 2 4 Molar flow rate (kmol/d) 1000 4000 3600 200 3400 400 3000 CO 0.3 0.26 0.24 0.25 0.5 0.25 0.25 0.25 H2 0.6 0.53 0.47 0.24 0.06 0.5 0.5 N2 CH3OH 0.1 0.21 0.25 0.25 1 Step 1 Overall mass balance To find the extent of reaction, all this 3 equation is needed let ysco = 0.75- y6H, Component mass balance find Stream number 3 = 300 - 400y6co 3 (600 - 400y6H)/2 1 1 molar flow rate 2 (kmol/d) 1000 400 equate 1 and 2 300 - 400y6co= (600 - 400y6H)/2 y1, N2 (n1) = n6(0.25) Yoco (n6) = 0.3(1000) – 5 Y6H2 (n6) = 0.6(1000) – 25 1 = y6co + Y6H2 + 0.25 N2 0.1 0.25 CO 0.3 0.25 subsutitute y6co and solved for y6H 300 - 400(0.75 - y6H) = (600 - 400Y6H)/2 H2 0.6 0.5 Y6H = 0.50 solved Y6co = 0.75 - y6H = 0.25 3619
n7 3000 i n6 n5 n1 n2 n3 Reactor CO + H2 - CH3OH Condenser 1000 0.3 0.6 n4 0.1
Transcribed Image Text:n7 3000 i n6 n5 n1 n2 n3 Reactor CO + H2 - CH3OH Condenser 1000 0.3 0.6 n4 0.1
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