N3/4 4 e4x dx 5) 1 + e8x

Calculus: Early Transcendentals
8th Edition
ISBN:9781285741550
Author:James Stewart
Publisher:James Stewart
Chapter1: Functions And Models
Section: Chapter Questions
Problem 1RCC: (a) What is a function? What are its domain and range? (b) What is the graph of a function? (c) How...
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Use the substitution formula to evaluate the integral

### Integral Calculation Problem

Consider the following integral:

\[ 
5) \int_{0}^{\ln \sqrt{3}/4} \frac{4e^{4x}}{1 + e^{8x}} \, dx 
\]

This expression represents a definite integral with the following components:

- **Integration Limits**: The lower limit of integration is \(0\), and the upper limit is \(\ln \sqrt{3}/4\).
- **Integrand**: The function being integrated is \(\frac{4e^{4x}}{1 + e^{8x}}\).
- **Variable of Integration**: The differential \(dx\) indicates that the integration is performed with respect to the variable \(x\).

The integral's value represents the area under the curve of the function \(\frac{4e^{4x}}{1 + e^{8x}}\) between the limits \(x = 0\) and \(x = \ln \sqrt{3}/4\). 

This type of problem is commonly encountered in calculus courses focusing on the application of integrals. It may require techniques such as substitution to evaluate efficiently.
Transcribed Image Text:### Integral Calculation Problem Consider the following integral: \[ 5) \int_{0}^{\ln \sqrt{3}/4} \frac{4e^{4x}}{1 + e^{8x}} \, dx \] This expression represents a definite integral with the following components: - **Integration Limits**: The lower limit of integration is \(0\), and the upper limit is \(\ln \sqrt{3}/4\). - **Integrand**: The function being integrated is \(\frac{4e^{4x}}{1 + e^{8x}}\). - **Variable of Integration**: The differential \(dx\) indicates that the integration is performed with respect to the variable \(x\). The integral's value represents the area under the curve of the function \(\frac{4e^{4x}}{1 + e^{8x}}\) between the limits \(x = 0\) and \(x = \ln \sqrt{3}/4\). This type of problem is commonly encountered in calculus courses focusing on the application of integrals. It may require techniques such as substitution to evaluate efficiently.
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