N2(g) +202(g) 2 NO2(g) Initially, 0.45 mol/L of nitrogen and 0.68 mol/L of oxygen are introduced into a container. What are the equilibrium values of all the species? O[N₂] = 0.44 M [02] = 0.66 M #3 3 [NO₂] = 0.020 M O[N₂] = 0.66 M [NO₂] = 0.44 M [2] - O[N₂] = 0.44 M [NO₂] = 0.44 M [0₂] = 0.020 M 80 F3 O[N₂] = 0.020 M - C. U2U IVE [NO₂] = 0.020 M [0₂] = 0.020 M 54 $ 4 000 000 F4 % 5 6 MacBook Air & 7 K = 1.96 x 10-3 F7 00 * 8 DII FB 9 DD F9 0 C F10 11 d F11 + 11
N2(g) +202(g) 2 NO2(g) Initially, 0.45 mol/L of nitrogen and 0.68 mol/L of oxygen are introduced into a container. What are the equilibrium values of all the species? O[N₂] = 0.44 M [02] = 0.66 M #3 3 [NO₂] = 0.020 M O[N₂] = 0.66 M [NO₂] = 0.44 M [2] - O[N₂] = 0.44 M [NO₂] = 0.44 M [0₂] = 0.020 M 80 F3 O[N₂] = 0.020 M - C. U2U IVE [NO₂] = 0.020 M [0₂] = 0.020 M 54 $ 4 000 000 F4 % 5 6 MacBook Air & 7 K = 1.96 x 10-3 F7 00 * 8 DII FB 9 DD F9 0 C F10 11 d F11 + 11
Chemistry
10th Edition
ISBN:9781305957404
Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Chapter1: Chemical Foundations
Section: Chapter Questions
Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...
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Question
1.
![F2
N2(g) + 202(g)
2 NO2(g)
Initially, 0.45 mol/L of nitrogen and 0.68 mol/L of oxygen are introduced into a
container. What are the equilibrium values of all the species?
O[N₂] = 0.44 M
[0₂] = 0.66 M
#3
O[N₂] = 0.66 M
[NO₂] = 0.020 M
E
D
[NO₂] = 0.44 M
[2] U. UZU IVE
80
F3
[N₂] = 0.44 M
[NO₂] = 0.44 M
[0₂] = 0.020 M
O[N₂] = 0.020 M
C
[NO2] = 0.020 M
[0₂] = 0.020 M
$
4
888
F4
R
F
67 do
%
5
V
F5
T
G
^
6
MacBook Air
B
F6
Y
I
v lo
7
F7
U
N
K = 1.96 x 10-3
* 00
8
J
DII
F8
1
M
(
9
K
DD
F9
O
)
0
1
L
F10
P
>
.
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Transcribed Image Text:F2
N2(g) + 202(g)
2 NO2(g)
Initially, 0.45 mol/L of nitrogen and 0.68 mol/L of oxygen are introduced into a
container. What are the equilibrium values of all the species?
O[N₂] = 0.44 M
[0₂] = 0.66 M
#3
O[N₂] = 0.66 M
[NO₂] = 0.020 M
E
D
[NO₂] = 0.44 M
[2] U. UZU IVE
80
F3
[N₂] = 0.44 M
[NO₂] = 0.44 M
[0₂] = 0.020 M
O[N₂] = 0.020 M
C
[NO2] = 0.020 M
[0₂] = 0.020 M
$
4
888
F4
R
F
67 do
%
5
V
F5
T
G
^
6
MacBook Air
B
F6
Y
I
v lo
7
F7
U
N
K = 1.96 x 10-3
* 00
8
J
DII
F8
1
M
(
9
K
DD
F9
O
)
0
1
L
F10
P
>
.
F11
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