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N2(g) +202(g) 2 NO2(g) Initially, 0.45 mol/L of nitrogen and 0.68 mol/L of oxygen are introduced into a container. What are the equilibrium values of all the species? O[N₂] = 0.44 M [02] = 0.66 M #3 3 [NO₂] = 0.020 M O[N₂] = 0.66 M [NO₂] = 0.44 M [2] - O[N₂] = 0.44 M [NO₂] = 0.44 M [0₂] = 0.020 M 80 F3 O[N₂] = 0.020 M - C. U2U IVE [NO₂] = 0.020 M [0₂] = 0.020 M 54 $ 4 000 000 F4 % 5 6 MacBook Air & 7 K = 1.96 x 10-3 F7 00 * 8 DII FB 9 DD F9 0 C F10 11 d F11 + 11

N2(g) +202(g) 2 NO2(g) Initially, 0.45 mol/L of nitrogen and 0.68 mol/L of oxygen are introduced into a container. What are the equilibrium values of all the species? O[N₂] = 0.44 M [02] = 0.66 M #3 3 [NO₂] = 0.020 M O[N₂] = 0.66 M [NO₂] = 0.44 M [2] - O[N₂] = 0.44 M [NO₂] = 0.44 M [0₂] = 0.020 M 80 F3 O[N₂] = 0.020 M - C. U2U IVE [NO₂] = 0.020 M [0₂] = 0.020 M 54 $ 4 000 000 F4 % 5 6 MacBook Air & 7 K = 1.96 x 10-3 F7 00 * 8 DII FB 9 DD F9 0 C F10 11 d F11 + 11

Chemistry
Chemistry
10th Edition
ISBN:9781305957404
Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Chapter1: Chemical Foundations
Section: Chapter Questions
Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...
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F2 N2(g) + 202(g) 2 NO2(g) Initially, 0.45 mol/L of nitrogen and 0.68 mol/L of oxygen are introduced into a container. What are the equilibrium values of all the species? O[N₂] = 0.44 M [0₂] = 0.66 M #3 O[N₂] = 0.66 M [NO₂] = 0.020 M E D [NO₂] = 0.44 M [2] U. UZU IVE 80 F3 [N₂] = 0.44 M [NO₂] = 0.44 M [0₂] = 0.020 M O[N₂] = 0.020 M C [NO2] = 0.020 M [0₂] = 0.020 M $ 4 888 F4 R F 67 do % 5 V F5 T G ^ 6 MacBook Air B F6 Y I v lo 7 F7 U N K = 1.96 x 10-3 * 00 8 J DII F8 1 M ( 9 K DD F9 O ) 0 1 L F10 P > . F11
Transcribed Image Text:F2 N2(g) + 202(g) 2 NO2(g) Initially, 0.45 mol/L of nitrogen and 0.68 mol/L of oxygen are introduced into a container. What are the equilibrium values of all the species? O[N₂] = 0.44 M [0₂] = 0.66 M #3 O[N₂] = 0.66 M [NO₂] = 0.020 M E D [NO₂] = 0.44 M [2] U. UZU IVE 80 F3 [N₂] = 0.44 M [NO₂] = 0.44 M [0₂] = 0.020 M O[N₂] = 0.020 M C [NO2] = 0.020 M [0₂] = 0.020 M $ 4 888 F4 R F 67 do % 5 V F5 T G ^ 6 MacBook Air B F6 Y I v lo 7 F7 U N K = 1.96 x 10-3 * 00 8 J DII F8 1 M ( 9 K DD F9 O ) 0 1 L F10 P > . F11
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