N2 (g) + 3H2 ↔ 2NH3 The standard free energy change at 500 Kelvins is -33.2 kj / mol and the equilibrium constant K = 6.59x105 if the initial conditions in an experiment are P (H2) = 0.25 atm, P (N2) = 0.87 atm and P (NH3) = 12.9 atm Comment on the direction of the reaction by calculating ∆G for the reaction under these conditions. Products Entrants Just write "1 or 2" for the answer.
N2 (g) + 3H2 ↔ 2NH3 The standard free energy change at 500 Kelvins is -33.2 kj / mol and the equilibrium constant K = 6.59x105 if the initial conditions in an experiment are P (H2) = 0.25 atm, P (N2) = 0.87 atm and P (NH3) = 12.9 atm Comment on the direction of the reaction by calculating ∆G for the reaction under these conditions. Products Entrants Just write "1 or 2" for the answer.
Chemistry
10th Edition
ISBN:9781305957404
Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Chapter1: Chemical Foundations
Section: Chapter Questions
Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...
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N2 (g) + 3H2 ↔ 2NH3
The standard free energy change at 500 Kelvins is -33.2 kj / mol and the equilibrium constant K = 6.59x105 if the initial conditions in an experiment are P (H2) = 0.25 atm, P (N2) = 0.87 atm and P (NH3) = 12.9 atm Comment on the direction of the reaction by calculating ∆G for the reaction under these conditions.
Products
Entrants
Just write "1 or 2" for the answer.
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