N What If?How would your answers to parts (a) and (b) of this problem change if the 0 kg block was now stacked on top of the 1.0 kg block? Assume that the 2.0 kg block sticks to and does not slide on the 1.0 kg block when the system is accelerated. (Enter the acceleration in m/s2 to the right and the tension in N.)

College Physics
11th Edition
ISBN:9781305952300
Author:Raymond A. Serway, Chris Vuille
Publisher:Raymond A. Serway, Chris Vuille
Chapter1: Units, Trigonometry. And Vectors
Section: Chapter Questions
Problem 1CQ: Estimate the order of magnitude of the length, in meters, of each of the following; (a) a mouse, (b)...
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Hi, the first three parts of this problem have been answered, I just need the answer for the part below that is in BOLD.  Thanks!

Assume the three blocks (m1= 1.0 kg, m2 = 2.0 kg,, and m3 = 3.5 kg) portrayed in the figure below move on a frictionless surface and a force F = 48 N acts as shown on the 3.5 kg block.  Three blocks of mass m1m2, and m3 are placed on a horizontal surface. Block m1 is taller than m2 and touches its leftmost surface. Block m3 is some distance to the right of block m2. A cord, passing over block m2, connects blocks m1 and m3. A horizontal force vector F is applied to block m3 and directed rightward.

  • Determine the acceleration given this system (in m/s2to the right).

         a = (F) / (m1 + m2 + m3) = (48.0) / (1+2+3.5) = 7.3846 ≈ 7.39 m/s2

  • Determine the tension in the cord connecting the 5kg and the 1.0 kg blocks (in N).

F-T = m3a

(48) – T = (3.5)(7.39 m/s2)

T = 48 – 25.865 = 22.135 ≈ 22.14 N

  • Determine the force exerted by the 1.0 kg block on the 2.0 kg block (in N).

F1 = m2a

F1 = (2.0) (7.39 m/s2) = 14.78 ≈ 14.80 N

What If?How would your answers to parts (a) and (b) of this problem change if the 0 kg block was now stacked on top of the 1.0 kg block? Assume that the 2.0 kg block sticks to and does not slide on the 1.0 kg block when the system is accelerated. (Enter the acceleration in m/s2 to the right and the tension in N.)

m_
m2
F
Transcribed Image Text:m_ m2 F
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