n The population of heights of students of a large university is approximately normal with a inches. While testing the hypotheses M en an observed SRS of size . - 2s gave Kg = 72. Using significance level - - an, test the hypotheses. Then construct a confidence interval with confidence level i - -- am How does the confidence interval provide a method of testing the hypotheses The following "answers- have been proposed. cao The GLR test rejects g if > 215. For the given information, z = 3.75. Therefore, we reject 1, The 99 percent confidence interval for , is pa, n641. Since the null hypothesis value of , - o is not inside the confidence interval, it indicates that n, should be rejected. dbe The GLR test rejects my if 231 For the given information, z- 135. Therefore, we reject , The 9 percent confidence interval for , is panse, 70) Since the mll hypothesis value of » - e is not inside the confidence interval, it indicates that se should be rejected. c The GLR test rejects , if z. , 1 For the given information, z - 3.75. Therefore, we reject n, The 99 percent confidence interval for, is pa36,73 64). Since the null hypothesis value of , - en is not inside the confidence interval, it indicates that 0g should be rejected. ado The GLR est rejects Mg if > 255 For the given information, z-175. Therefore, we reject , The 99 percent confidence interval for, is 4, 74O. Since the null hypothesis value of - is not inside the confidence interval, it indicates that , should be rejected. den None of the above. The correct answer is
n The population of heights of students of a large university is approximately normal with a inches. While testing the hypotheses M en an observed SRS of size . - 2s gave Kg = 72. Using significance level - - an, test the hypotheses. Then construct a confidence interval with confidence level i - -- am How does the confidence interval provide a method of testing the hypotheses The following "answers- have been proposed. cao The GLR test rejects g if > 215. For the given information, z = 3.75. Therefore, we reject 1, The 99 percent confidence interval for , is pa, n641. Since the null hypothesis value of , - o is not inside the confidence interval, it indicates that n, should be rejected. dbe The GLR test rejects my if 231 For the given information, z- 135. Therefore, we reject , The 9 percent confidence interval for , is panse, 70) Since the mll hypothesis value of » - e is not inside the confidence interval, it indicates that se should be rejected. c The GLR test rejects , if z. , 1 For the given information, z - 3.75. Therefore, we reject n, The 99 percent confidence interval for, is pa36,73 64). Since the null hypothesis value of , - en is not inside the confidence interval, it indicates that 0g should be rejected. ado The GLR est rejects Mg if > 255 For the given information, z-175. Therefore, we reject , The 99 percent confidence interval for, is 4, 74O. Since the null hypothesis value of - is not inside the confidence interval, it indicates that , should be rejected. den None of the above. The correct answer is
MATLAB: An Introduction with Applications
6th Edition
ISBN:9781119256830
Author:Amos Gilat
Publisher:Amos Gilat
Chapter1: Starting With Matlab
Section: Chapter Questions
Problem 1P
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![(7) The population of heights of students of a large university is approximately normal with o = 4 inches. While testing the hypotheses
Ho: µ = 69 inches,
H1: µ + 69 inches,
an observed SRS of size n = 25 gave X25 = 72. Using significance level a = 0.01, test the hypotheses. Then construct a confidence interval with confidence level 1- a = 0.99. How does the confidence interval provide a method of testing the hypotheses:
The following `answers" have been proposed.
(a) The GLR test rejects Ho if
|Xn - 69||
Z =
> 2,575.
4/5
For the given information, z = 3.75. Therefore, we reject Ho. The 99 percent confidence interval for u is [70.136, 73.864]. Since the null hypothesis value of µ = 69 is not inside the confidence interval, it indicates that Họ should be rejected.
(b) The GLR test rejects Ho if
|Xn – 69|
Z =
> 2,33,
4/5
For the given information, z = 3.75. Therefore, we reject Ho. The 99 percent confidence interval for u is [69.94, 74.06]. Since the null hypothesis value of u = 69 is not inside the confidence interval, it indicates that Ho should be rejected.
(c) The GLR test rejects Ho if
|Xn – 69||
Z =
> 2,33.
4/5
For the given information, z = 3.75. Therefore, we reject Ho. The 99 percent confidence interval for u is [70.136, 73.864]. Since the null hypothesis value of u = 69 is not inside the confidence interval, it indicates that Ho should be rejected.
(d) The GLR test rejects Ho if
|Xn – 69||
Z =
> 2.575.
4/5
For the given information, z = 3.75. Therefore, we reject Ho. The 99 percent confidence interval for u is [69.94, 74.06]. Since the null hypothesis value of µ = 69 is not inside the confidence interval, it indicates that Ho should be rejected.
(e) None of the above.
The correct answer is
(a)
(b)
(d)
N/A
(Select One)](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2F6214fda8-f992-4e88-b320-5195339361f5%2F50b2ed78-3adb-4a07-bd70-c842486fc31e%2Fv9hrq48_processed.png&w=3840&q=75)
Transcribed Image Text:(7) The population of heights of students of a large university is approximately normal with o = 4 inches. While testing the hypotheses
Ho: µ = 69 inches,
H1: µ + 69 inches,
an observed SRS of size n = 25 gave X25 = 72. Using significance level a = 0.01, test the hypotheses. Then construct a confidence interval with confidence level 1- a = 0.99. How does the confidence interval provide a method of testing the hypotheses:
The following `answers" have been proposed.
(a) The GLR test rejects Ho if
|Xn - 69||
Z =
> 2,575.
4/5
For the given information, z = 3.75. Therefore, we reject Ho. The 99 percent confidence interval for u is [70.136, 73.864]. Since the null hypothesis value of µ = 69 is not inside the confidence interval, it indicates that Họ should be rejected.
(b) The GLR test rejects Ho if
|Xn – 69|
Z =
> 2,33,
4/5
For the given information, z = 3.75. Therefore, we reject Ho. The 99 percent confidence interval for u is [69.94, 74.06]. Since the null hypothesis value of u = 69 is not inside the confidence interval, it indicates that Ho should be rejected.
(c) The GLR test rejects Ho if
|Xn – 69||
Z =
> 2,33.
4/5
For the given information, z = 3.75. Therefore, we reject Ho. The 99 percent confidence interval for u is [70.136, 73.864]. Since the null hypothesis value of u = 69 is not inside the confidence interval, it indicates that Ho should be rejected.
(d) The GLR test rejects Ho if
|Xn – 69||
Z =
> 2.575.
4/5
For the given information, z = 3.75. Therefore, we reject Ho. The 99 percent confidence interval for u is [69.94, 74.06]. Since the null hypothesis value of µ = 69 is not inside the confidence interval, it indicates that Ho should be rejected.
(e) None of the above.
The correct answer is
(a)
(b)
(d)
N/A
(Select One)
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