n the case of diffraction by a rectangular slit of width a, it can be proved that the amplitude distribution as a function of the angular position θ is given by A = A₀ sin(u)/u, where A₀ is a constant, u = (πa sin θ)/λ and the function sin(u)/u must be replaced by 1 if u=0. As seen in class, the intensity minima occur for sin θ = nλ, n=1, 2, 3, ... (a) What is the equation that determines the positions of the intensity maxima? (b) What is the angular position θ₁ of the first maximum, excluding the central maximum
n the case of diffraction by a rectangular slit of width a, it can be proved that the amplitude distribution as a function of the angular position θ is given by A = A₀ sin(u)/u, where A₀ is a constant, u = (πa sin θ)/λ and the function sin(u)/u must be replaced by 1 if u=0. As seen in class, the intensity minima occur for sin θ = nλ, n=1, 2, 3, ... (a) What is the equation that determines the positions of the intensity maxima? (b) What is the angular position θ₁ of the first maximum, excluding the central maximum
Related questions
Question
In the case of diffraction by a rectangular slit of width a, it can be proved that the amplitude distribution as a function of the angular position θ is given by A = A₀ sin(u)/u, where A₀ is a constant, u = (πa sin θ)/λ and the function sin(u)/u must be replaced by 1 if u=0. As seen in class, the intensity minima occur for sin θ = nλ, n=1, 2, 3, ... (a) What is the equation that determines the positions of the intensity maxima? (b) What is the angular position θ₁ of the first maximum, excluding the central maximum
( ) (a) u = nπ, n = 1, 2, 3, … (b) sen θ₁ = λ/a
( ) (a) u = nπ/2, n = 1, 3, 5, … (b) sen θ₁= λ/2a
( ) (a) tg u - u = 0 (b) sen θ₁ = 4,49341 λ/πa
( ) (a) tg u - u = 0 (b) sen θ₁= 2λ/πa
( ) (a) tg u - u = 0 (b) sen θ₁ = 3λ/πa
( ) (a) tg u - u = 0 (b) sen θ₁ = 2λ/a
( ) (a) tg u - u = 0 (b) sen θ₁ = 3λ/a
( ) (a) tg u - u = 0 (b) sen θ₁ = 4,49341 λ/a
( ) (a) cos u - u = 0 (b) sen θ₁ = 0,7391 λ/πa
( ) (a) cos u - u = 0 (b) sen θ₁ = 2λ/πa
( ) (a) cos u - u = 0 (b) sen θ₁ = 3λ/πa
( ) (a) cos u - u = 0 (b) sen θ₁ = 2λ/a
( ) (a) cos u - u = 0 (b) sen θ₁ = 3λ/a
( ) (a) cos u - u = 0 (b) sen θ₁ = 0,7391 λ/a
Expert Solution
Step 1 To determine,
(a) What is the equation that determines the positions of the intensity maxima? (b) What is the angular position θ₁ of the first maximum, excluding the central maximum.
Step by step
Solved in 2 steps
