n range (ncol): if((i%2==0) and (i
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import csv
dicta = {}
csv_reader = csv.reader(f, delimiter=") for row in csv_reader:
ncol = len(row) for i in range (ncol):
if((i%2==0) and (i<ncol-1) and (int(row[i+1]) < 9 or
int(row[i+1])>17)):
dicta[row[i]] = row[i+1]
if len(dicta)==0:
dictionary
print("No anomaly login attemps")
else:
print("Anomaly login attempts: ",end = "")
for key, value in dicta.items():
print(key:value,end="").
print("\n")
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Solved in 2 steps
- You may have found it somewhat tedious and unpleasant to use the debugger and visualizer to verify the correctness of your addFirst and addLast methods. There is also the problem that such manual verification becomes stale as soon as you change your code. Imagine that you made some minor but uncertain change to addLast]. To verify that you didn't break anything you'd have to go back and do that whole process again. Yuck. What we really want are some automated tests. But unfortunately there's no easy way to verify correctness of addFirst and addLast] if those are the only two methods we've implemented. That is, there's currently no way to iterate over our list and get bad its values and see that they are correct. That's where the toList method comes in. When called, this method returns a List representation of the Deque. For example, if the Deque has had addLast (5) addLast (9) addLast (10), then addFirst (3) called on it, then the result of toList() should be a List with 3 at the…def upgrade_stations(threshold: int, num_bikes: int, stations: List["Station"]) -> int: """Modify each station in stations that has a capacity that is less than threshold by adding num_bikes to the capacity and bikes available counts. Modify each station at most once. Return the total number of bikes that were added to the bike share network. Precondition: num_bikes >= 0For any element in keysList with a value smaller than 40, print the corresponding value in itemsList, followed by a comma (no spaces). Ex: If keysList = {32, 105, 101, 35} and itemsList = {10, 20, 30, 40}, print: 10,40, #include <iostream>#include <string.h>using namespace std; int main() { const int SIZE_LIST = 4; int keysList[SIZE_LIST]; int itemsList[SIZE_LIST]; int i; cin >> keysList[0]; cin >> keysList[1]; cin >> keysList[2]; cin >> keysList[3]; cin >> itemsList[0]; cin >> itemsList[1]; cin >> itemsList[2]; cin >> itemsList[3]; /* Your code goes here */ cout << endl; return 0;}
- In cell C18 type a VLOOKUP function to find the corresponding letter grade (from column D) for the name in A18. The table array parameter is the same as in B18. Type FALSE for the range lookup parameter. Copy the formula in C18 to C19:C22Notice this formula works correctly for all cells. Range lookup of FALSE means do an exact match on the lookup value whether or not the table array is sorted by its first column. In cell E11, type an IF function that compares the score in B11 with the minimum score to pass in A5. If the comparison value is true, display Pass. Otherwise, display Fail. Copy the formula in E11 to E12:E15. Did you use appropriate absolute and relative references so the formula copied properly? In cell F11, type an IF function that compares the grade in D11 with the letter F (type F). If these two are not equal, display Pass. Otherwise, display Fail. Copy the formula in F11 to F12:F15For any element in keysList with a value greater than 50, print the corresponding value in itemsList, followed by a comma (no spaces). Ex: If the input is: 32 105 101 35 10 20 30 40 the output is: 20,30, 1 #include 2 3 int main(void) { const int SIZE_LIST = 4; int keysList[SIZE_LIST]; int itemsList[SIZE_LIST]; int i; 4 6 7 8 scanf("%d", &keysList[0]); scanf ("%d", &keysList[1]); scanf("%d", &keysList[2]); scanf("%d", &keysList[3]); 10 11 12 13 scanf ("%d", &itemsList[0]); scanf ("%d", &itemsList[1]); scanf("%d", &itemsList[2]); scanf ("%d", &itemsList[3]); 14 15 16 17 18 19 /* Your code goes here */ 20 21 printf("\n"); 22 23 return 0; 24 }# TODO y_values = display(y_values) todo_check([ (y_values.shape == (120,),'y_values does not have the correct shape of (120,)'), (np.all(np.isclose(y_values,…
- def city_dict(adict): """ Question 6 -Given a dictionary that maps a person to a list of countries they want to travel to, return a dictionary with the value being the list sorted by the last letter in each countries name. If two countries have the same last letter, sort by the first letter. -For an extra challenge, try doing this in one line (Optional). Args: adict (dict) Returns: dict >>> city_dict({"Pablo": ["Belgium", "Canada", "Germany"], "Athena": ["Italy", "France", "Egypt"], "Liv": ["Japan", "Bolivia", "Greece"]}) {'Pablo': ['Canada', 'Belgium', 'Germany'], 'Athena': ['France', 'Egypt', 'Italy'], 'Liv': ['Bolivia', 'Greece', 'Japan']} >>> city_dict({"Jacob": ["Bahamas", "Brazil", "Chile"], "Lexi": ["Colombia", "Finland", "Panama"], "Emily": ["Ireland", "Russia", "Kenya", "Jordan"]}) {'Jacob': ['Chile', 'Brazil', 'Bahamas'], 'Lexi': ['Colombia', 'Panama', 'Finland'], 'Emily': ['Kenya',…List List countries countries.Add("India"); countries.Add("Australia"); countries.Add("Japan"); countries.Add("Canada"); countries.Add("Mexico"); = new List(); res = ""; foreach (string cin countries) res += c + ",";Add each element in origList with the corresponding value in offsetAmount. Print each sum followed by a space. Ex: If origList = {40, 50, 60, 70} and offsetAmount = {5, 7, 3, 0}, print: 45 57 63 70 #include <iostream>#include <vector>using namespace std; int main() {const int NUM_VALS = 4;vector<int> origList(NUM_VALS);vector<int> offsetAmount(NUM_VALS);unsigned int i; for (i = 0; i < origList.size(); ++i) {cin >> origList.at(i);} for (i = 0; i < offsetAmount.size(); ++i) {cin >> offsetAmount.at(i);} cout << endl; return 0;} Please help me with this problem using c++.
- A synopsis of the advantages and disadvantages of global connection in the context of cloud computing.The show_sequence function at below is part of chapter 3 program. What kind of passing does this function us and why? void show_sequence(sequence display) // Library facilities used: iostream{ for (display.start( ); display.is_item( ); display.advance( )) cout << display.current( ) << endl;} Group of answer choices It uses a value parameter. The reason is the advancing of the current element through the sequence would alter the actual argument. That is what we want. It uses a value parameter. The reason is the we don't want the advancing of the current element through the sequence to alter the actual argument. It uses a geneeral parameter. The reason is the we don't want the advancing of the current element through the sequence to alter the actual argument. It uses a reference parameter. The reason is the we don't want the advancing of the current element through the sequence to alter the actual argument. It uses a reference parameter. The reason is…In python: student_dict is a dictionary with students' name and pedometer reading pairs. A new student is read from input and added into student_dict. For each student in student_dict, output the student's name, followed by "'s pedometer reading: ", and the student's pedometer reading. Then, assign average_value with the average of all the pedometer readings in student_dict..
