(N) (R) (V) = (A - y)² (B −y) = (y-A) (B-y) = y(y² + B) Answer: Answer: (P) = (A+y)(B+ y)² da (S) dx (y - A)²(y + B) dy (W) = y(y² - B) Answer: Answer: @ -ZISSSS (T) = y(A - y²) da (Z) = (A-y)(B-y) dy PINESSSTIZZ XXS S \IZZ = 1²(y + A) ~~\~t. \\\/ //
(N) (R) (V) = (A - y)² (B −y) = (y-A) (B-y) = y(y² + B) Answer: Answer: (P) = (A+y)(B+ y)² da (S) dx (y - A)²(y + B) dy (W) = y(y² - B) Answer: Answer: @ -ZISSSS (T) = y(A - y²) da (Z) = (A-y)(B-y) dy PINESSSTIZZ XXS S \IZZ = 1²(y + A) ~~\~t. \\\/ //
Advanced Engineering Mathematics
10th Edition
ISBN:9780470458365
Author:Erwin Kreyszig
Publisher:Erwin Kreyszig
Chapter2: Second-order Linear Odes
Section: Chapter Questions
Problem 1RQ
Related questions
Question
100%
Each graph below is a slope field for one of the
the differential equation in the blank. There is only one correct differential equation for each slope field. Assume
A > 0 and B < 0 are constants.
I understand the concept of plugging in the values of x and y to find dy/dx. I didn't understand what to do because of A & B.
Do I just set A as a number great than 0?
And B as a number less than 0 and plug and chug for dy/dx?
Transcribed Image Text:Z
(R)
dy
y
dy
dx
= (A - y)² (B - y)
=
(y - A)(B - y)
(V) y = y(y² + B)
Answer:
Answer:
(P)
(S)
dy
da
dx
=
= (A+y)(B+ y)²
=
(y - A)²(y + B)
(W) = y(y² – B)
y
ZINN
Answer:
Answer:
= (A - y) (B - y)
(T) = y(A - y²)
dr
(Z) dy = y²(y + A)
I
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