n and be able to transform an s-domain solution rcuits with 5Ω + 20 u(t) Vx 0.5 F не 0.2 Ux 10 a b 222 1 H

Introductory Circuit Analysis (13th Edition)
13th Edition
ISBN:9780133923605
Author:Robert L. Boylestad
Publisher:Robert L. Boylestad
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n and be able to transform an s-domain solution
rcuits with
5Ω
www
20 u(t) vx
0.5 F
не
0.2 0.
1Ω
wwww
a 2 Ω
-Www
b
1H
Transcribed Image Text:n and be able to transform an s-domain solution rcuits with 5Ω www 20 u(t) vx 0.5 F не 0.2 0. 1Ω wwww a 2 Ω -Www b 1H
13.6 The initial charge on the capacitor in the circuit
shown is zero.
a) Find the s-domain Thévenin equivalent circuit
with respect to terminals a and b.
b) Find the s-domain expression for the current
that the circuit delivers to a load consisting of a
1 H inductor in series with a 2 2 resistor.
Transcribed Image Text:13.6 The initial charge on the capacitor in the circuit shown is zero. a) Find the s-domain Thévenin equivalent circuit with respect to terminals a and b. b) Find the s-domain expression for the current that the circuit delivers to a load consisting of a 1 H inductor in series with a 2 2 resistor.
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Part A is incorrect. Part B is correct. Attached is the correct answer, please fix and show how to arrive at the correct answer for part A. 

13.6 The initial charge on the capacitor in the circuit
shown is zero.
a) Find the s-domain Thévenin equivalent circuit
with respect to terminals a and b.
b) Find the s-domain expression for the current
that the circuit delivers to a load consisting of a
1 H inductor in series with a 2 2 resistor.
Answer: (a) Vrh = Vab = [20(s +2.4)]/[s(s+ 2)],
ZTh = 5(s+ 2.8)/(s + 2);
(b) lab = [20(s+ 2.4)]/[s(s+ 3) (s + 6)].
T
ntar Problem 13 37
Transcribed Image Text:13.6 The initial charge on the capacitor in the circuit shown is zero. a) Find the s-domain Thévenin equivalent circuit with respect to terminals a and b. b) Find the s-domain expression for the current that the circuit delivers to a load consisting of a 1 H inductor in series with a 2 2 resistor. Answer: (a) Vrh = Vab = [20(s +2.4)]/[s(s+ 2)], ZTh = 5(s+ 2.8)/(s + 2); (b) lab = [20(s+ 2.4)]/[s(s+ 3) (s + 6)]. T ntar Problem 13 37
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