n a survey of 378 randomly selected gun owners, it was found that 83 of them said they owned a gun primarily for protection. Find the margin of error and 95% confidence interval for the percentage of all gun owners who would say that they own a gun primarily for protection. Round all answers to 2 decimal places. Margin of Error (as a percentage):  Confidence Interval: % to %

Q: In a survey of 419 randomly selected gun owners, it was found that 85 of them said they owned a gun…

A: Obtain the margin of error at the 95% confidence interval. The margin of error at the 95% confidence…

Q: Given 25 confidence intervals in the figure to the left, which of the following is the most likely…

A: The confidence interval is an inference process which gives the range of plausible values of…

Q: In a recent poll, 410 people were asked if they liked dogs, and 85% said they did. Find the margin…

A: Given that, p^=0.85n=410 Critical value: By using the z-tables, the critical value at 1% level of…

Q: Use the sample data and confidence level given below to complete parts  (c).   A research institute…

A: It is given that, the number of respondents said yes (x) is 587 and the sample size (n) is 912.  The…

Q: Use the sample data and confidence level given below to complete parts (a) through (d). A research…

A:

Q: A 95% confidence interval for the proportion p active voters in the municipality of Aibonito is 0.57…

A:

Q: A research institute poll asked respondents if they felt vulnerable to identity theft. In the poll,…

A:

Q: In a recent poll, 340 people were asked if they liked dogs, and 31% said they did. Find the margin…

A:

Q: A new fertilizer was applied to the soil of 238 bean plants. 34% showed increased growth. Find the…

A: Given Information : A new fertilizer was applied to the soil of 238 bean plants. 34% showed…

Q: A research institute poll asked respondents if they felt vulnerable to identity theft. In the​ poll,…

A:

Q: A researcher would like to know the proportion of the households that has a cable subscription. She…

A:

Q: A poll of 657 home sellers found that 29.8% were trying to sell their home without a real estate…

A:

Q: Use the sample data and confidence level given below to complete parts  (b)   A research institute…

A: Margin of error can be calculated as shown below.

Q: In a recent poll, 130 people were asked if they liked dogs, and 24% said they did. Find the margin…

A: Given, Total number of people = 130 Probability that a person likes a dog = 0.24 z value at 99%…

Q: In a survey of 126 randomly selected gun owners, it was found that 53 of them said they owned a gun…

A: Find z-critical value: For the two-tail test, Area on each tail. Area to the left of the normal…

Q: Educational Television In a random sample of 205 people, 143 said that they watched educational…

A:

Q: In a recent poll, 500 people were asked if they liked dogs, and 54% said they did. Find the margin…

A: Here we need to find the Margin of error corresponding to 95% confidence level.

Q: A new fertilizer was applied to the soil of 222 bean plants. 28% showed increased growth. Find the…

A: Given Information: Sample Size, n =222Sample Proportion, p^=28% =0.28 To find out the margin of…

Q: A poll of 2657 U.S. adults found that 86% regularly used Facebook as a news source. Find the margin…

A: Given that, n = 2657 Point estimate = sample proportion =  = 0.86 1 -  = 1 - 0.86 = 0.14

Q: A poll of 2977 U.S. adults found that 28% regularly used Facebook as a news source. Find the margin…

A: Solution: Given information: n = 2977 Sample size  p^= 0.28  Sample proportion.

Q: A poll of 1103 home sellers found that 29.8% were trying to sell their home without a real estate…

A: Given,sample size(n)=1103sample proportion(p^)=0.298margin of error(E)=0.027

Q: A research institute poll asked respondents if they felt vulnerable to identity theft. In the​ poll,…

A:

Q: In a recent poll, 600 people were asked if they liked dogs, and 58% said they did. Find the margin…

A:

Q: Use the given degree of confidence and sample data to construct a confidence interval for the…

A: Obtain the 99% confidence interval for the true proportion of all college students who own a car.…

Q: In a recent poll, 240 people were asked if they liked dogs, and 32% said they did. Find the margin…

A: Find z-critical value:…

Q: Use the sample data and confidence level given below to complete parts (a) through (d). A research…

A:

Q: In a recent poll, 300 people were asked if they liked dogs, and 73% said they did. Find the margin…

A:

Q: n a recent poll, 330 people were asked if they liked dogs, and 30% said they did. Find the margin of…

A: given data, n=330p=0.30CI=0.99α=1-0.99=0.01ME=?

Q: Use the sample data and confidence level given below to complete parts​ (a) through​ (d).   A…

A:

Q: a survey of 183 randomly selected gun owners, it was found that 67 of them said they owned a gun…

A: Provided information is, in a survey of 183 randomly selected gun owners, it was found that 67 of…

Q: In a recent poll, 250 people were asked if they liked dogs, and 21% said they did. Find the margin…

A: Sample size=n=250P=21%=0.2195% of confidence interval is

Q: Use the sample data and confidence level given below to complete parts (a) through (d). A research…

A: Sample size n=972 Number of successes x=577 Confidence level 99%

Q: A new fertilizer was applied to the soil of 218 bean plants. 27% showed increased growth. Find the…

A: Given Information: Sample size (n) = 218 Proportion p^= 27% = 0.27 To find the margin of error and…

Q: A new fertilizer was applied to the soil of 151 bean plants. 72% showed increased growth. Find the…

A: The known values are, P^=0.72, n=151. Using Standard normal table, the critical value for two-tailed…

Q: Use the sample data and confidence level given below to complete parts (a) through (d). A research…

A: We have given that in the poll, n = 1078, x = 507 Best point estimate of population proportion p =…

Q: In a recent poll, 530 people were asked if they liked dogs, and 95% said they did. Find the margin…

A: Given, n=530 p=0.95 Confidence level = 0.95 Critical value for 95% confidence level is 1.96.

Q: A poll of 1021 U.S. adults found that 46% regularly used Facebook as a news source. Find the…

A: Given, n = 1021 p^=0.46 q^ = 1 - p^ = 1 - 0.46 = 0.54 α=0.1

Q: A new fertilizer was applied to the soil of 123 bean plants. 85% showed increased growth. Find the…

A: Find z-critical value: For the two-tail test, Area on each tail. Area to the left of the normal…

Q: A survey asked, "How many tattoos do you currently have on your body?" Of the 1241 males surveyed,…

A: We have given that,  X1 = 182, n1 = 1241  And  X2 = 139, n2 = 1047 Then,  We will find the 99%…

Q: In a survey, people were asked whether they thought sun went around the planet Earth or vice versa.…

A: a. It was found that out of the 2152 people, 389 thought the sun went around earth. The sample size…

Q: Use the sample data and confidence level given below to complete parts (a) through (d). A research…

A: Given Data Sample Size, n = 992 Number of successes, x = 581.0 confidence level,c=…

Q: A poll of 2612 U.S. adults found that 15% regularly used Facebook as a news source. Find the margin…

A: The margin of error is defined as MOEγ=zγ×σn,γ is the confidence level,σ is the sample standard…

Q: In a survey of 431 randomly selected gun owners, it was found that 74 of them said they owned a gun…

A:

Estimation

A new framework of data analysis where the new statistical methods are used for interpreting the results and analyzing the data is known as estimation in statistics.