n a survey of 378 randomly selected gun owners, it was found that 83 of them said they owned a gun primarily for protection. Find the margin of error and 95% confidence interval for the percentage of all gun owners who would say that they own a gun primarily for protection. Round all answers to 2 decimal places. Margin of Error (as a percentage):  Confidence Interval: % to %

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A: Obtain the margin of error at the 95% confidence interval. The margin of error at the 95% confidence…

Q: Use the sample data and confidence level given below to complete parts  (c).   A research institute…

A: It is given that, the number of respondents said yes (x) is 587 and the sample size (n) is 912.  The…

Q: A survey asked, "How many tattoos do you currently have on your body?" Of the 1209 males surveyed,…

A:

Q: A survey of 700 non-fatal accidents showed that 167 involved uninsured drivers. Construct a 99%…

A: Given data,n=700x=167Point estimate isp=xn=167700=0.2386Construct a 99% confidence interval?

Q: Use the sample data and confidence level given below to complete parts (a) through (d). A research…

A: From the provided information, Sample size (n) = 902 Out of which 507 said yes that is x = 507

Q: In a survey of 3700 TV viewers, 834 said they watch network news programs. Find the margin of error…

A: Solution

Q: A research institute poll asked respondents if they felt vulnerable to identity theft. In the poll,…

A:

Q: Find the margin of error for the 95% confidence interval used to estimate the population proportion.…

A: Confidence level = 95% Sample size (n) = 2440 Sample proportion (p̂) = 0.70

Q: Suppose you calculate a 99% confidence interval to be: 13.05 to 20.75. Determine the margin of error

A: Given data: The given upper limit is b=20.75. The given lower limit is a=13.05.   The expression for…

Q: Find the margin of error and confidence interval for the percentage of U.S. adults who regularly use…

A:

Q: A new fertilizer was applied to the soil of 199 bean plants. 48% showed increased growth. Find the…

A: Margin of error for proportion is given by, MOE= z*√pq/n Where P Is proportion and Q= 1-P n is…

Q: The. Nielsen television ratings used a random sample of 2,000 homes and found that 45% of the homes…

A:

Q: A survey of 26 individuals found that they spent an average of $39.21 on exercise attire for the…

A: Confidence interval is an inference process which is used to estimate the population parameter. The…

Q: Use the sample data and confidence level given below to complete parts  (b)   A research institute…

A: Margin of error can be calculated as shown below.

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A: Find z-critical value: For the two-tail test, Area on each tail. Area to the left of the normal…

Q: Educational Television In a random sample of 205 people, 143 said that they watched educational…

A:

Q: Use the sample data and confidence level given below to complete parts (a) through (d). A research…

A: Given that    A research institute poll asked respondents if they felt vulnerable to identity theft.…

Q: A poll of 2929 U.S. adults found that 85% regularly used Facebook as a news source. Find the…

A:

Q: In a survey of 2255 adults, 741 say they believe in UFOS. Construct a 95% confidence interval for…

A:

Q: When 307 college students are randomly selected and surveyed, it is found that 128 own a car. Find a…

A: Given Data Sample Size, n = 307 Number of successes, x = 128 Significance level,…

Q: A poll of 2657 U.S. adults found that 86% regularly used Facebook as a news source. Find the margin…

A: Given that, n = 2657 Point estimate = sample proportion =  = 0.86 1 -  = 1 - 0.86 = 0.14

Q: A poll of 2977 U.S. adults found that 28% regularly used Facebook as a news source. Find the margin…

A: Solution: Given information: n = 2977 Sample size  p^= 0.28  Sample proportion.

Q: Use the given degree of confidence and sample data to construct a confidence interval for the…

A: Obtain the 99% confidence interval for the true proportion of all college students who own a car.…

Q: Use the sample data and confidence level given below to complete parts​ (a) through​ (d). A research…

A: It is given that n = 1,005 and x = 520.

Q: Use the sample data and confidence level given below to complete parts​ (a) through​ (d).   A…

A:

Q: Use the sample data and confidence level given below to complete parts​ (a) through​ (d). A research…

A: The random variable X follows normal distribution. We have to construct 95% confidence interval.…

Q: Use the sample data and confidence level given below to complete parts (a) through (d). A research…

A: According to the given information in this question  There are more than three subparts according to…

Q: a survey of 183 randomly selected gun owners, it was found that 67 of them said they owned a gun…

A: Provided information is, in a survey of 183 randomly selected gun owners, it was found that 67 of…

Q: A new fertilizer was applied to the soil of 222 bean plants. 28% showed increased growth. Find the…

A:

Q: Use the sample data and confidence level given below to complete parts (a) through (d). A research…

A: Sample size n=972 Number of successes x=577 Confidence level 99%

Q: A new fertilizer was applied to the soil of 218 bean plants. 27% showed increased growth. Find the…

A: Given Information: Sample size (n) = 218 Proportion p^= 27% = 0.27 To find the margin of error and…

Q: In a survey of 3089 adults aged 57 through 85 years, it was found that 88.5% of them used at least…

A:

Q: In a survey of 2291 adults, 743 say they believe in UFOs. Construct a 99% confidence interval for…

A: sample size(n)=2291No. of adults say they believe in UFOs(x)=743

Q: Use the sample data and confidence level given below to complete parts (a) through (d). A research…

A: We have given that in the poll, n = 1078, x = 507 Best point estimate of population proportion p =…

Q: A confidence interval was constructed to approximate a population proportion. The interval was from…

A: Given Data Lower limit,LL = 12.5 upper limit,UL = 18.5

Q: Use the sample data and confidence level given below to complete parts​ (a) through​ (d).   A…

A: Given, The best sample proportion is,

Estimation

A new framework of data analysis where the new statistical methods are used for interpreting the results and analyzing the data is known as estimation in statistics.