n= 886 i 1 2 4 Pi 0.14 0.34 0.23 0.29
MATLAB: An Introduction with Applications
6th Edition
ISBN:9781119256830
Author:Amos Gilat
Publisher:Amos Gilat
Chapter1: Starting With Matlab
Section: Chapter Questions
Problem 1P
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Step 1
If the expected frequencies are not equal, then E=np for each category.
Where, n is the total number of frequencies, k is the categories and p is the probability of occurrence.
Here, the total number of frequencies is 886 and there are 4 outcomes then k is 4. Also, the probabilities are different. Thus, by using the second method the expected frequencies are calculated as follows.
Digits |
E.frequency |
E1 |
124.04 (=(886)(0.14)) |
E2 |
301.24 (=(886)(0.34) |
E3 |
203.78 (=(886)(0.23)) |
E4 |
256.94 (=(886)(0.29)) |
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