Task 3: Electric potential energy and electric potential 1. Examine the charge distribution shown. Sphere 1 has a charge of +3.0 × 10 4 C; sphere 2 has a charge of -3.0 × 10-4 C; and sphere 3 has a charge of +3.0 × 10-4 C. Assume that Coulomb's constant, (k) is equal to 9.0 × 109 N m² Show all your work when completing each of these questions. N 4.24 m. 3.00 m 4.24 m 3.00 m 3.00 m 93 92 91 a. Determine the total electric potential energy for the charge distribution. b. Determine the total electric potential at point Z. n = 3 S₂ PS2 e S P.S A n = 2 P A H m = 1 n = 1 m = 0 n = 1 m=2 n = 2 m = 1

Physics for Scientists and Engineers with Modern Physics
10th Edition
ISBN:9781337553292
Author:Raymond A. Serway, John W. Jewett
Publisher:Raymond A. Serway, John W. Jewett
Chapter43: Nuclear Physics
Section: Chapter Questions
Problem 44P
Question
Task 3: Electric potential energy and electric potential
1. Examine the charge distribution shown. Sphere 1 has a charge of
+3.0 × 10 4 C; sphere 2 has a charge of -3.0 × 10-4 C; and sphere
3 has a charge of +3.0 × 10-4 C. Assume that Coulomb's constant, (k) is equal
to 9.0 × 109 N m²
Show all your work when completing each of these questions.
N
4.24 m.
3.00 m
4.24 m
3.00 m
3.00 m
93
92
91
a. Determine the total electric potential energy for the charge distribution.
b. Determine the total electric potential at point Z.
Transcribed Image Text:Task 3: Electric potential energy and electric potential 1. Examine the charge distribution shown. Sphere 1 has a charge of +3.0 × 10 4 C; sphere 2 has a charge of -3.0 × 10-4 C; and sphere 3 has a charge of +3.0 × 10-4 C. Assume that Coulomb's constant, (k) is equal to 9.0 × 109 N m² Show all your work when completing each of these questions. N 4.24 m. 3.00 m 4.24 m 3.00 m 3.00 m 93 92 91 a. Determine the total electric potential energy for the charge distribution. b. Determine the total electric potential at point Z.
n = 3
S₂
PS2
e
S
P.S
A
n = 2
P
A
H
m = 1
n = 1
m = 0
n = 1
m=2
n = 2
m = 1
Transcribed Image Text:n = 3 S₂ PS2 e S P.S A n = 2 P A H m = 1 n = 1 m = 0 n = 1 m=2 n = 2 m = 1
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