UFC LMy-usinevcu myVC x C A ball XM-u cos 8loncapa.vcu.edu/res/vcu/phys201/Motion_2D/projectile-motion_num_arc_reverse.problemCourse Contents » ... » HW #4 (due Mon 2/13 at 10 am) » projectile-motion_num_arc_reverse.problem110MaximumHeight, hRange, RComputer's answer now shown above. You are correct.Your receipt no. is 154-2638 ?What is the maximum height the cannonball?125 meters.A cannonball is fired from a gun and lands 410 meters away at a time 10 seconds.What is the y-component of the initial velocity?50 m/s.LON-XComputer's answer now shown above. You are correct.Your receipt no. is 154-9294 ?What is the x-component of the initial velocity?41 m/s.Submit Answer Tries 0/2Computer's answer now shown above. You are correct.Your receipt no. is 154-7491 ?What is the muzzle velocity of this projectile?m/s.Submit Answer Tries 0/2What is the angle of inclination of this projectile?LON-Xdegrees from the horizontal.Previous TriesLON-X CA can XPrevious TriesPrevious TriesS Philad X4MathuX

My-usine M₂- cos 8 Maximum Height, h A cannonball is fired from a gun and lands 410 meters away at a time 10 seconds. What is the y-component of the initial velocity? 50 m/s. Range, R Computer's answer now shown above. You are correct. Your receipt no. is 154-2638 What is the maximum height of the cannonball? 125 meters. Computer's answer now shown above. You are correct. Your receipt no. is 154-9294 ? What is the x-component of the initial velocity? #1 m/s. Computer's answer now shown above. You are correct. Your receipt no. is 154-7491 ? Submit Answer Tries 0/2 What is the muzzle velocity of this projectile? m/s. Submit Answer Tries 0/2 What is the angle of inclination of this projectile? degrees from the horizontal. Previous Tries Previous Tries Previous Tries 4

My-usine M₂- cos 8 Maximum Height, h A cannonball is fired from a gun and lands 410 meters away at a time 10 seconds. What is the y-component of the initial velocity? 50 m/s. Range, R Computer's answer now shown above. You are correct. Your receipt no. is 154-2638 What is the maximum height of the cannonball? 125 meters. Computer's answer now shown above. You are correct. Your receipt no. is 154-9294 ? What is the x-component of the initial velocity? #1 m/s. Computer's answer now shown above. You are correct. Your receipt no. is 154-7491 ? Submit Answer Tries 0/2 What is the muzzle velocity of this projectile? m/s. Submit Answer Tries 0/2 What is the angle of inclination of this projectile? degrees from the horizontal. Previous Tries Previous Tries Previous Tries 4

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Question

UFC L
My-usine
vcu myVC x C A ball X
M-u cos 8
loncapa.vcu.edu/res/vcu/phys201/Motion_2D/projectile-motion_num_arc_reverse.problem
Course Contents » ... » HW #4 (due Mon 2/13 at 10 am) » projectile-motion_num_arc_reverse.problem
110
Maximum
Height, h
Range, R
Computer's answer now shown above. You are correct.
Your receipt no. is 154-2638 ?
What is the maximum height the cannonball?
125 meters.
A cannonball is fired from a gun and lands 410 meters away at a time 10 seconds.
What is the y-component of the initial velocity?
50 m/s.
LON-X
Computer's answer now shown above. You are correct.
Your receipt no. is 154-9294 ?
What is the x-component of the initial velocity?
41 m/s.
Submit Answer Tries 0/2
Computer's answer now shown above. You are correct.
Your receipt no. is 154-7491 ?
What is the muzzle velocity of this projectile?
m/s.
Submit Answer Tries 0/2
What is the angle of inclination of this projectile?
LON-X
degrees from the horizontal.
Previous Tries
LON-X CA can X
Previous Tries
Previous Tries
S Philad X
4
Mathu
X

Expert Solution

Introduction:

Disclaimer: “Since you have asked posted a question with multiple sub-parts, we will solve the first three sub-parts for you. To get remaining sub-part solved please repost the complete question and mention the sub parts to be solved.”

We are given horizontal range of ball. We are also given time of flight for the ball.

The time of flight is given as

$T = \frac{2 u \sin θ}{g}$

Here $u, θ$ are initial velocity and angle of projection respectively.

The range is the horizontal component of velocity times the time of flight. We hence obtain 2 equations of motion which we solve simultaneously to find velocity and angle.