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My question is for the part circled in green only. The question is why does logb(b) =1

My question is for the part circled in green only. The question is why does logb(b) =1

Calculus: Early Transcendentals
Calculus: Early Transcendentals
8th Edition
ISBN:9781285741550
Author:James Stewart
Publisher:James Stewart
Chapter1: Functions And Models
Section: Chapter Questions
Problem 1RCC: (a) What is a function? What are its domain and range? (b) What is the graph of a function? (c) How...
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My question is for the part circled in green only. The question is why does logb(b) =1

4. The final answer is 3 log (m) +2 log b(n) - · 5. Substitute this into the result found earlier. 4. (q) Boy 5. = (q)ª Bo1 ( = (q)ª Boj aɔu %3D 1. %3D 5. 4. 5. The logarithm – log (b) can still be simplified. 4 This gives 3 log (m)+ 2 log b(n)- log b(b). 1. by 5. The expression can be further simplified by multiplying through 1. (9)" B01 - (") ° Bo1 + (z,u) ° Bo1)2 The given expression can then be rewritten. %3D %3D Similarly, log (nº) = 8 log (n) and log , (b°) =5 log (b). %3D products. Use the Power Rule to write the logarithms of powers as () " B01 - (6") ª Bo1 + (z,w) ª 6o1 ) Section 3.9 homework-Jessica 21
Transcribed Image Text:4. The final answer is 3 log (m) +2 log b(n) - · 5. Substitute this into the result found earlier. 4. (q) Boy 5. = (q)ª Bo1 ( = (q)ª Boj aɔu %3D 1. %3D 5. 4. 5. The logarithm – log (b) can still be simplified. 4 This gives 3 log (m)+ 2 log b(n)- log b(b). 1. by 5. The expression can be further simplified by multiplying through 1. (9)" B01 - (") ° Bo1 + (z,u) ° Bo1)2 The given expression can then be rewritten. %3D %3D Similarly, log (nº) = 8 log (n) and log , (b°) =5 log (b). %3D products. Use the Power Rule to write the logarithms of powers as () " B01 - (6") ª Bo1 + (z,w) ª 6o1 ) Section 3.9 homework-Jessica 21
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