Homework Help is Here – Start Your Trial Now!
Math
Calculus
MY NOTES ASK YOUR TEACHER The rate of change of the function f(x) = sin(x) + csc(x) is given by the expression cos(x) - csc(x) cot(x). Show that the expression for the rate of change can also be written as -cos(x) cot²(x). cos(x)-csc(x) cot(x) = cos(x) - sin(x) sin(x) = (cos(x)) sin²(x)) -csc²(x)) = (cos(x)) = (-cos(x))([ |-¹)

MY NOTES ASK YOUR TEACHER The rate of change of the function f(x) = sin(x) + csc(x) is given by the expression cos(x) - csc(x) cot(x). Show that the expression for the rate of change can also be written as -cos(x) cot²(x). cos(x)-csc(x) cot(x) = cos(x) - sin(x) sin(x) = (cos(x)) sin²(x)) -csc²(x)) = (cos(x)) = (-cos(x))([ |-¹)

Calculus: Early Transcendentals
Calculus: Early Transcendentals
8th Edition
ISBN:9781285741550
Author:James Stewart
Publisher:James Stewart
Chapter1: Functions And Models
Section: Chapter Questions
Problem 1RCC: (a) What is a function? What are its domain and range? (b) What is the graph of a function? (c) How...
See similar textbooks
icon
Related questions
Question
Help me show work
MY NOTES ASK YOUR TEACHER The rate of change of the function f(x) = sin(x) + csc(x) is given by the expression cos(x) - csc(x) cot(x). Show that the expression for the rate of change can also be written as -cos(x) cot²(x). cos(x)-csc(x) cot(x) = cos(x) - 1 sin(x) sin(x) = (cos(x))( sin²(x)) - csc²(x)) = (cos(x))( = (-cos(x)) -1) = -cos(x) cot²(x)
Transcribed Image Text:MY NOTES ASK YOUR TEACHER The rate of change of the function f(x) = sin(x) + csc(x) is given by the expression cos(x) - csc(x) cot(x). Show that the expression for the rate of change can also be written as -cos(x) cot²(x). cos(x)-csc(x) cot(x) = cos(x) - 1 sin(x) sin(x) = (cos(x))( sin²(x)) - csc²(x)) = (cos(x))( = (-cos(x)) -1) = -cos(x) cot²(x)
Verify the identity. 9 cos² B-9 sin² B = 18 cos² B-9 9 cos² B-9 sin² B = 9 cos² B-9(1- cos²B = 9 cos² B + 9 cos²B X = 18 cos² B-9 X 9
Transcribed Image Text:Verify the identity. 9 cos² B-9 sin² B = 18 cos² B-9 9 cos² B-9 sin² B = 9 cos² B-9(1- cos²B = 9 cos² B + 9 cos²B X = 18 cos² B-9 X 9
Expert Solution
trending now

Trending now

This is a popular solution!

steps

Step by step

Solved in 2 steps with 1 images

SEE SOLUTIONCheck out a sample Q&A here
Blurred answer
Recommended textbooks for you
Calculus: Early Transcendentals
Calculus: Early Transcendentals
Calculus
ISBN:
9781285741550
Author:
James Stewart
Publisher:
Cengage Learning
Thomas' Calculus (14th Edition)
Thomas' Calculus (14th Edition)
Calculus
ISBN:
9780134438986
Author:
Joel R. Hass, Christopher E. Heil, Maurice D. Weir
Publisher:
PEARSON
Calculus: Early Transcendentals (3rd Edition)
Calculus: Early Transcendentals (3rd Edition)
Calculus
ISBN:
9780134763644
Author:
William L. Briggs, Lyle Cochran, Bernard Gillett, Eric Schulz
Publisher:
PEARSON
Calculus: Early Transcendentals
Calculus: Early Transcendentals
Calculus
ISBN:
9781319050740
Author:
Jon Rogawski, Colin Adams, Robert Franzosa
Publisher:
W. H. Freeman
Precalculus
Precalculus
Calculus
ISBN:
9780135189405
Author:
Michael Sullivan
Publisher:
PEARSON
Calculus: Early Transcendental Functions
Calculus: Early Transcendental Functions
Calculus
ISBN:
9781337552516
Author:
Ron Larson, Bruce H. Edwards
Publisher:
Cengage Learning
SEE MORE TEXTBOOKS