My issue: I wrote my questions in bold in the comments of the code Java code:  import java.util.Scanner; public class DescendingOrder { // TODO: Write a void method selectionSortDescendTrace() that takes // an integer array and the number of elements in the array as arguments, // and sorts the array into descending order. public static void selectionSortDescendTrace(int [] numbers, int numElements) { //my code starts here int i; int j; int elementIndex; int temp; //loop in ascending order using textbook example for (i=0; i < numElements-1; ++i) { index=i; for (j=i+1; j < numElements; ++j) { if (numbers[j] < numbers[elementIndex]) { elementIndex=j; } } //swap using textbook example temp=numbers[i]; numbers[i]=numbers[elementIndex]; numbers[elementIndex]=temp; //I don't know how to put it in descending order. Is it using a loop? //where do I put in descending order? Is it in the method definitions or main method ???  } } //my code ends here public static void main(String[] args) { Scanner scnr = new Scanner(System.in); int input, i = 0; int numElements = 0; int [] numbers = new int[10]; // TODO: Read in a list of up to 10 positive integers; stop when // -1 is read. Then call selectionSortDescendTrace() method. //my code starts here for (i=0; i < numbers.length; ++i) { input=scnr.nextInt(); numbers[i]=input; if (numbers[i]==-1) { break; numElements++; } //selectionSortDescendTrace(); //what goes inside the parenthesis??? //my code ends here } }

Database System Concepts
7th Edition
ISBN:9780078022159
Author:Abraham Silberschatz Professor, Henry F. Korth, S. Sudarshan
Publisher:Abraham Silberschatz Professor, Henry F. Korth, S. Sudarshan
Chapter1: Introduction
Section: Chapter Questions
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My issue:

I wrote my questions in bold in the comments of the code

Java code: 

import java.util.Scanner;

public class DescendingOrder {
// TODO: Write a void method selectionSortDescendTrace() that takes
// an integer array and the number of elements in the array as arguments,
// and sorts the array into descending order.
public static void selectionSortDescendTrace(int [] numbers, int numElements) {
//my code starts here
int i;
int j;
int elementIndex;
int temp;
//loop in ascending order using textbook example
for (i=0; i < numElements-1; ++i) {
index=i;
for (j=i+1; j < numElements; ++j) {
if (numbers[j] < numbers[elementIndex]) {
elementIndex=j;
}
}
//swap using textbook example
temp=numbers[i];
numbers[i]=numbers[elementIndex];
numbers[elementIndex]=temp;

//I don't know how to put it in descending order. Is it using a loop?
//where do I put in descending order? Is it in the method definitions or main method ??? 
}
}
//my code ends here


public static void main(String[] args) {
Scanner scnr = new Scanner(System.in);

int input, i = 0;
int numElements = 0;
int [] numbers = new int[10];

// TODO: Read in a list of up to 10 positive integers; stop when
// -1 is read. Then call selectionSortDescendTrace() method.

//my code starts here

for (i=0; i < numbers.length; ++i) {
input=scnr.nextInt();
numbers[i]=input;
if (numbers[i]==-1) {
break;
numElements++;
}
//selectionSortDescendTrace(); //what goes inside the parenthesis???

//my code ends here

}
}

 

8.10 LAB: Descending selection sort with output during execution
Write a void method selectionSortDescendTrace() that takes an integer array, and sorts the array into descending order. The method
should use nested loops and output the array after each iteration of the outer loop, thus outputting the array N-1 times (where N is the
size). Complete main() to read in a list of up to 10 positive integers (ending in -1) and then call the selectionSortDescendTrace() method.
If the input is:
20 10 30 40 -1
then the output is:
40 10 30 20
40 30 10 20
40 30 20 10
Transcribed Image Text:8.10 LAB: Descending selection sort with output during execution Write a void method selectionSortDescendTrace() that takes an integer array, and sorts the array into descending order. The method should use nested loops and output the array after each iteration of the outer loop, thus outputting the array N-1 times (where N is the size). Complete main() to read in a list of up to 10 positive integers (ending in -1) and then call the selectionSortDescendTrace() method. If the input is: 20 10 30 40 -1 then the output is: 40 10 30 20 40 30 10 20 40 30 20 10
Selection sort has the advantage of being easy to code, involving one loop nested within another loop, as shown below.
Figure 8.6.1: Selection sort algorithm.
public class SelectionSort {
public static void selectionSort (int [] numbers) {
int i;
int j;
int indexSmallest;
int temp;
// Temporary variable for swap
for (i = e; i« numbers.length
1; ++i) {
// Find index of smallest remaining element
indexSmallest = i;
for (j = i + 1; j< numbers.length; ++j) {
if (numbers[j] < numbers [indexSmallest]) {
indexSmallest - j;
}
// Swap numbers[i] and numbers[indexSmallest]
temp = numbers[i];
numbers[i] = numbers[indexSmallest];
numbers[indexSmallest] = temp;
UNSORTED: 10 2 78 4 45 32 7 11
SORTED: 2 4 7 10 11 32 45 78
public static void main(String [] args)
int numbers [] = {10, 2, 78, 4, 45, 32, 7, 11};
int i;
System.out.print ("UNSORTED: ");
for (i = e; i < numbers.length; ++i)
System.out.print (numbers[i] +
System.out
In()3B
/* initial call to selection sort with index */
selectionSort(numbers);
System.out.print("SORTED: ");
for (i = e; i < numbers.length; ++i) {
System.out.print (numbers[i] + " ");
System.out.println();
Feedback?
Selection sort may require a large number of comparisons. The selection sort algorithm runtime is O(N2). If a list has N elements, the outer
loop executes N -1 times. For each of those N -1 outer loop executions, the inner loop executes an average of * times. So the total
Transcribed Image Text:Selection sort has the advantage of being easy to code, involving one loop nested within another loop, as shown below. Figure 8.6.1: Selection sort algorithm. public class SelectionSort { public static void selectionSort (int [] numbers) { int i; int j; int indexSmallest; int temp; // Temporary variable for swap for (i = e; i« numbers.length 1; ++i) { // Find index of smallest remaining element indexSmallest = i; for (j = i + 1; j< numbers.length; ++j) { if (numbers[j] < numbers [indexSmallest]) { indexSmallest - j; } // Swap numbers[i] and numbers[indexSmallest] temp = numbers[i]; numbers[i] = numbers[indexSmallest]; numbers[indexSmallest] = temp; UNSORTED: 10 2 78 4 45 32 7 11 SORTED: 2 4 7 10 11 32 45 78 public static void main(String [] args) int numbers [] = {10, 2, 78, 4, 45, 32, 7, 11}; int i; System.out.print ("UNSORTED: "); for (i = e; i < numbers.length; ++i) System.out.print (numbers[i] + System.out In()3B /* initial call to selection sort with index */ selectionSort(numbers); System.out.print("SORTED: "); for (i = e; i < numbers.length; ++i) { System.out.print (numbers[i] + " "); System.out.println(); Feedback? Selection sort may require a large number of comparisons. The selection sort algorithm runtime is O(N2). If a list has N elements, the outer loop executes N -1 times. For each of those N -1 outer loop executions, the inner loop executes an average of * times. So the total
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