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my distri andom samp In this age the average time spent watching TV per week was 10.78 hours. Test using the critical value method if the population mean time spent watching TV in the age group 14 - 25 years has changed, using a = 0.01. Select one: O a. Zcrit = ±2.33, reject Ho. b. Zcrit = ±2.575, do not reject Ho.

my distri andom samp In this age the average time spent watching TV per week was 10.78 hours. Test using the critical value method if the population mean time spent watching TV in the age group 14 - 25 years has changed, using a = 0.01. Select one: O a. Zcrit = ±2.33, reject Ho. b. Zcrit = ±2.575, do not reject Ho.

MATLAB: An Introduction with Applications
MATLAB: An Introduction with Applications
6th Edition
ISBN:9781119256830
Author:Amos Gilat
Publisher:Amos Gilat
Chapter1: Starting With Matlab
Section: Chapter Questions
Problem 1P
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According to a study conducted by Deloitte, people between the ages of 14 - 25 years watch 10.5 hours of TV on average per week with a population standard deviation of 0.5 hours. Assume the population is normally distributed. A random sample of 20 individuals in this age group showed the average time spent watching TV per week was 10.78 hours. Test using the critical value method if the population mean time spent watching TV in the age group 14 - 25 years has changed, using a = 0.01. Select one: a. Zcrit = ±2.33, reject Ho. O b. Zcrit = ±2.575, do not reject Ho. O c. Zcrit = 2.33, reject Ho. d. Zcrit = 2.575, do not reject Ho.
Transcribed Image Text:According to a study conducted by Deloitte, people between the ages of 14 - 25 years watch 10.5 hours of TV on average per week with a population standard deviation of 0.5 hours. Assume the population is normally distributed. A random sample of 20 individuals in this age group showed the average time spent watching TV per week was 10.78 hours. Test using the critical value method if the population mean time spent watching TV in the age group 14 - 25 years has changed, using a = 0.01. Select one: a. Zcrit = ±2.33, reject Ho. O b. Zcrit = ±2.575, do not reject Ho. O c. Zcrit = 2.33, reject Ho. d. Zcrit = 2.575, do not reject Ho.
Expert Solution
Step 1: Determine the given data in the question

Let mu be the population's mean time spent watching TV.

Given that,

Population mean left parenthesis mu right parenthesis equals 10.5

Population standard deviation left parenthesis sigma right parenthesis equals 0.5

No. of individuals left parenthesis n right parenthesis equals 20

Sample mean left parenthesis x with bar on top right parenthesis equals 10.78

Assume the level of significance left parenthesis alpha right parenthesis equals 0.01

1 minus alpha over 2 equals 1 minus fraction numerator 0.01 over denominator 2 end fraction equals 0.995


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