= mx + b, f(-2) = 3, and f (4) = 1 What is the value of b? 04 011 3 73 01 0-1/

Calculus: Early Transcendentals
8th Edition
ISBN:9781285741550
Author:James Stewart
Publisher:James Stewart
Chapter1: Functions And Models
Section: Chapter Questions
Problem 1RCC: (a) What is a function? What are its domain and range? (b) What is the graph of a function? (c) How...
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The problem presented is to find the value of \( b \) in the linear function \( f(x) = mx + b \), given that \( f(-2) = 3 \) and \( f(4) = 1 \).

### Problem

Given:
- \( f(x) = mx + b \)
- \( f(-2) = 3 \)
- \( f(4) = 1 \)

**Question:** What is the value of \( b \)?

### Options
- \( \circ \) 4
- \( \circ \) \(\frac{11}{3}\)
- \( \circ \) \(\frac{7}{3}\)
- \( \circ \) 1
- \( \circ \) \(-\frac{1}{3}\)
Transcribed Image Text:The problem presented is to find the value of \( b \) in the linear function \( f(x) = mx + b \), given that \( f(-2) = 3 \) and \( f(4) = 1 \). ### Problem Given: - \( f(x) = mx + b \) - \( f(-2) = 3 \) - \( f(4) = 1 \) **Question:** What is the value of \( b \)? ### Options - \( \circ \) 4 - \( \circ \) \(\frac{11}{3}\) - \( \circ \) \(\frac{7}{3}\) - \( \circ \) 1 - \( \circ \) \(-\frac{1}{3}\)
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