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Multiplying the denominator and numerator of (4.24) by 4 [(B1 + B3 + B5) + A (B2 + B4)]? we get 4[A(B1+B3+95)-(82+B4)][S])[(8)+B3+Bs)(a2+a4)+A(B2+B4) (a,+az+as)] (B2+B4)-(B1+ß3+B3))(A+1)]| Y1 - P = S A (B2 + Ba) (S1 - 8)² – (B1 + B3 + B5) (Sı + 8)² S 2[(81 + B3 + B5) + A (B2 + B4)] (a1+a3 + a5) (S1 + 8) + S 2[(B1 + B3 + B5)+ A (B2 +Ba)] (a2 + a4) (S1 - 8) S 4[A(81+B3+B5)-(82+B4)][S1][(81+B3+Bs)(az+a4)+A(82+B4) (a1+ag+as)] (B2+B4)-(B1+ß3+Bs))(A+1)] S A (32 + B4) [S1]² – (B1 + B3 + Bs) [S1]² + S [A(B2 + B4) - (B1 + B3 + B5)]8² | +

Multiplying the denominator and numerator of (4.24) by 4 [(B1 + B3 + B5) + A (B2 + B4)]? we get 4[A(B1+B3+95)-(82+B4)][S])[(8)+B3+Bs)(a2+a4)+A(B2+B4) (a,+az+as)] (B2+B4)-(B1+ß3+B3))(A+1)]| Y1 - P = S A (B2 + Ba) (S1 - 8)² – (B1 + B3 + B5) (Sı + 8)² S 2[(81 + B3 + B5) + A (B2 + B4)] (a1+a3 + a5) (S1 + 8) + S 2[(B1 + B3 + B5)+ A (B2 +Ba)] (a2 + a4) (S1 - 8) S 4[A(81+B3+B5)-(82+B4)][S1][(81+B3+Bs)(az+a4)+A(82+B4) (a1+ag+as)] (B2+B4)-(B1+ß3+Bs))(A+1)] S A (32 + B4) [S1]² – (B1 + B3 + Bs) [S1]² + S [A(B2 + B4) - (B1 + B3 + B5)]8² | +

Advanced Engineering Mathematics
Advanced Engineering Mathematics
10th Edition
ISBN:9780470458365
Author:Erwin Kreyszig
Publisher:Erwin Kreyszig
Chapter2: Second-order Linear Odes
Section: Chapter Questions
Problem 1RQ
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Show me the steps of determine blue and inf is here. Explain step by step and i need every details.

(a1 + a3 + a5) P+(@2+a4) Q (B1 + B3 + B5) P + (82 + B4) Q [A (B1 + B3 + B3) – (B2 + Ba)]PQ + A (B2 + B4) Q² – (B1 + B3 + Bs) P2 Y1 – P = AQ + - P (B1 + Вз + B5) Р+ (B2 + Ba) Q (а1 + аз + о5) Р+ (02 + ад) Q (B1 + B3 + B5) P+(82+ B4) Q [A(B1+B3+B5)-(B2+B4)][S1][(B1+B3+B5)(a2+a4)+A(B2+B4) (@1+a3+as)] [(81+33+B5)+A(B2+34)]²[((82+B4)-(81+B3+B5))(A+1)] (B1 + B3 + B5) [(a1+a3+a5)-(a2+a4)]+8` 2[(B1+B3+B5)+A(82+B4)] [(a1+a3+a5)-(a2+a4)]-8 + (B2 + B4) (2(31+33+B5)+A(B2+Ba)] A (B2 + Ba) (ataz+a5)-(a2ta4)]-8' 2[(B1+33+B5)+A(B2+B4)] 2 [(@1+a3+a5)-(ag+a4)]+8` 2[(B1+33+B5)+A(ß2+B4)] [(ai+a3+a5)-(a2+a4)]-8 (B1 + B3 + B5) ( (B1 + B3 + B5) [(a1+a3+a5)-(a2+a4)]+8` 2[(B1+33+ß5)+A(B2+34)] )+ (B2 + B4) ( 2(3+33+B5)+A(B2+B4)] [(@1+a3+a5)-(a2+a4)]+8 2[(B1+B3+B5)+A(B2+B4)] [(a1+a3+a5)-(a2+a4)]+ô` 2[(81+33+B5)+A(ß2+B4)] ([(@1+a3+a5)-(az+a4)]-8` 2[(B1+B3+B3)+A(B2+B4)] [(a1+a3+a5)-(a2+a4)]-8 2[(B1+B3+B5)+A(B2+B4)] (a1 + az + a5) + (a2 + a4) (B1 + B3 + B5) + (B2 + B4) (4.24)
Transcribed Image Text:(a1 + a3 + a5) P+(@2+a4) Q (B1 + B3 + B5) P + (82 + B4) Q [A (B1 + B3 + B3) – (B2 + Ba)]PQ + A (B2 + B4) Q² – (B1 + B3 + Bs) P2 Y1 – P = AQ + - P (B1 + Вз + B5) Р+ (B2 + Ba) Q (а1 + аз + о5) Р+ (02 + ад) Q (B1 + B3 + B5) P+(82+ B4) Q [A(B1+B3+B5)-(B2+B4)][S1][(B1+B3+B5)(a2+a4)+A(B2+B4) (@1+a3+as)] [(81+33+B5)+A(B2+34)]²[((82+B4)-(81+B3+B5))(A+1)] (B1 + B3 + B5) [(a1+a3+a5)-(a2+a4)]+8` 2[(B1+B3+B5)+A(82+B4)] [(a1+a3+a5)-(a2+a4)]-8 + (B2 + B4) (2(31+33+B5)+A(B2+Ba)] A (B2 + Ba) (ataz+a5)-(a2ta4)]-8' 2[(B1+33+B5)+A(B2+B4)] 2 [(@1+a3+a5)-(ag+a4)]+8` 2[(B1+33+B5)+A(ß2+B4)] [(ai+a3+a5)-(a2+a4)]-8 (B1 + B3 + B5) ( (B1 + B3 + B5) [(a1+a3+a5)-(a2+a4)]+8` 2[(B1+33+ß5)+A(B2+34)] )+ (B2 + B4) ( 2(3+33+B5)+A(B2+B4)] [(@1+a3+a5)-(a2+a4)]+8 2[(B1+B3+B5)+A(B2+B4)] [(a1+a3+a5)-(a2+a4)]+ô` 2[(81+33+B5)+A(ß2+B4)] ([(@1+a3+a5)-(az+a4)]-8` 2[(B1+B3+B3)+A(B2+B4)] [(a1+a3+a5)-(a2+a4)]-8 2[(B1+B3+B5)+A(B2+B4)] (a1 + az + a5) + (a2 + a4) (B1 + B3 + B5) + (B2 + B4) (4.24)
Multiplying the denominator and numerator of (4.24) by 4 [(81 + B3 + B5) + A (B2 + Ba)]? we get 4[A(B1+B3+Bs)-(B2+B4)][S1][(31+B3+B5)(ag+a4)+A(B2+B4) (a1ta3+as)] T((B2+B4)-(B1+B3+Bs))(A+1)] Y1 – P = A (B2 + Ba) (S1 – 6)² – (B1 + B3 + B5) (Si + 6)? + S 2[(81 + B3 + B5)+ A (B2+ B4)] (aı + a3 + a5) (S1 + 8) S 2[(B1 + B3 + B5) + A (B2 + B4)] (a2 + a4) (S1 - 8) S 4[A(81+B3+35)-(82+84)][S1][(B,+83+B5)(a2+a4)+A(82+B4) (a+a3+as)] [((B2+84)-(81+B3+Bs))(A+1)]T S A (32 + B4) [Si]? – (B1 + 33 + B3) [Si]? S [A (32 + Ba) - (B1 + B3 + Bs)|8² + S 14 2[(81 + B3 + B5)+A (B2+B4)] (a2 + a4) [S1] + S 2[(B1 + B3 + B5) + A (B2 + Ba)] (a1 +a3 +a5) [S1] S 2A (B2 + Ba) [(a1 + a3 + a5) – (a2 +a4)] &+2 (B1 + B3 + B5) [S1] & S 2[(B1 + B3 + B5) + A (B2 + B4)] (a1 + a3 + a5) 6 – 2[(B1 + 3 + B5) + A (B2 + Ba)] (a2 + a4) 8 S 4[A(81+B3+Bs)-(32+B4)][S]((8,+83+Bs)(a2+a4)+A(B2+B4)(a1ta3+as)] T((B2+B4)-(B1+B3+Bs))(A+1)] 4[S1][(B1+B3+B5)(a2+a4)+A(B2+B4)(a+a3+as)][A(82+B4)-(B1+83+B3)] [((B2+B4)-(81+B3+Bs))(A+1)] A (B2 + Ba) [S1]? – (B1 + B3 + B5) [S1]² S [A (B2 + B4) – (B1 + B3 + Bs) [S1]² S 2[(B1 + B3 + B5)+ A (B2 + B4)] (a2 +a4) [S1] S 2[(B1 + B3 + B5) + A (B2 + Ba)] (aı +a3 +a5) [S1] 2 [S1] [(B1 + B3 + B5) + A (B2 + Ba)]S S 2 [S1] [(B1 + B3 + Bs) + A (B2 + Ba)]8 S 4 [S1] [(B1 + B3 + B5) (a2 + a4)+A (32+ B4) (a1 + a3 + a5)] S 4 [S1] [(B1 + B3 + Bs) (a2+ a4) + A (B2 + BA) (a1 + a3 + a5)] S 2[(a1 + a3 + as) - (a2 + a4)|[(P1 + B3 + Bs) + A (B2 + B4)]S S 2[(a1 + a3 + a5) - (a2+ a4)][(81 + B3 + B5) + A (B2 + B4)]8 + S 0. where S 2 [(B1 + B3 + Bs) + A (B2 + Ba)] × [(B1 + B3 + Bs) (Si + 8) + (B2 + Ba) (Sı – 8)] 15
Transcribed Image Text:Multiplying the denominator and numerator of (4.24) by 4 [(81 + B3 + B5) + A (B2 + Ba)]? we get 4[A(B1+B3+Bs)-(B2+B4)][S1][(31+B3+B5)(ag+a4)+A(B2+B4) (a1ta3+as)] T((B2+B4)-(B1+B3+Bs))(A+1)] Y1 – P = A (B2 + Ba) (S1 – 6)² – (B1 + B3 + B5) (Si + 6)? + S 2[(81 + B3 + B5)+ A (B2+ B4)] (aı + a3 + a5) (S1 + 8) S 2[(B1 + B3 + B5) + A (B2 + B4)] (a2 + a4) (S1 - 8) S 4[A(81+B3+35)-(82+84)][S1][(B,+83+B5)(a2+a4)+A(82+B4) (a+a3+as)] [((B2+84)-(81+B3+Bs))(A+1)]T S A (32 + B4) [Si]? – (B1 + 33 + B3) [Si]? S [A (32 + Ba) - (B1 + B3 + Bs)|8² + S 14 2[(81 + B3 + B5)+A (B2+B4)] (a2 + a4) [S1] + S 2[(B1 + B3 + B5) + A (B2 + Ba)] (a1 +a3 +a5) [S1] S 2A (B2 + Ba) [(a1 + a3 + a5) – (a2 +a4)] &+2 (B1 + B3 + B5) [S1] & S 2[(B1 + B3 + B5) + A (B2 + B4)] (a1 + a3 + a5) 6 – 2[(B1 + 3 + B5) + A (B2 + Ba)] (a2 + a4) 8 S 4[A(81+B3+Bs)-(32+B4)][S]((8,+83+Bs)(a2+a4)+A(B2+B4)(a1ta3+as)] T((B2+B4)-(B1+B3+Bs))(A+1)] 4[S1][(B1+B3+B5)(a2+a4)+A(B2+B4)(a+a3+as)][A(82+B4)-(B1+83+B3)] [((B2+B4)-(81+B3+Bs))(A+1)] A (B2 + Ba) [S1]? – (B1 + B3 + B5) [S1]² S [A (B2 + B4) – (B1 + B3 + Bs) [S1]² S 2[(B1 + B3 + B5)+ A (B2 + B4)] (a2 +a4) [S1] S 2[(B1 + B3 + B5) + A (B2 + Ba)] (aı +a3 +a5) [S1] 2 [S1] [(B1 + B3 + B5) + A (B2 + Ba)]S S 2 [S1] [(B1 + B3 + Bs) + A (B2 + Ba)]8 S 4 [S1] [(B1 + B3 + B5) (a2 + a4)+A (32+ B4) (a1 + a3 + a5)] S 4 [S1] [(B1 + B3 + Bs) (a2+ a4) + A (B2 + BA) (a1 + a3 + a5)] S 2[(a1 + a3 + as) - (a2 + a4)|[(P1 + B3 + Bs) + A (B2 + B4)]S S 2[(a1 + a3 + a5) - (a2+ a4)][(81 + B3 + B5) + A (B2 + B4)]8 + S 0. where S 2 [(B1 + B3 + Bs) + A (B2 + Ba)] × [(B1 + B3 + Bs) (Si + 8) + (B2 + Ba) (Sı – 8)] 15
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