Multiplying and DIviding Radical Expressions

Algebra and Trigonometry (6th Edition)
6th Edition
ISBN:9780134463216
Author:Robert F. Blitzer
Publisher:Robert F. Blitzer
ChapterP: Prerequisites: Fundamental Concepts Of Algebra
Section: Chapter Questions
Problem 1MCCP: In Exercises 1-25, simplify the given expression or perform the indicated operation (and simplify,...
icon
Related questions
Question

Multiplying and DIviding Radical Expressions

**Task: Multiply**

Given the expression: \((5 + \sqrt{3})(5 - \sqrt{3}) = \) [Box with the answer 22]

**Explanation:**
This expression is a difference of squares. It can be simplified by using the formula:
\[
(a + b)(a - b) = a^2 - b^2
\]

In this case, \(a = 5\) and \(b = \sqrt{3}\).

Applying the formula:
\[
(5 + \sqrt{3})(5 - \sqrt{3}) = 5^2 - (\sqrt{3})^2 = 25 - 3 = 22
\]

The final answer is 22, which is placed in the answer box.
Transcribed Image Text:**Task: Multiply** Given the expression: \((5 + \sqrt{3})(5 - \sqrt{3}) = \) [Box with the answer 22] **Explanation:** This expression is a difference of squares. It can be simplified by using the formula: \[ (a + b)(a - b) = a^2 - b^2 \] In this case, \(a = 5\) and \(b = \sqrt{3}\). Applying the formula: \[ (5 + \sqrt{3})(5 - \sqrt{3}) = 5^2 - (\sqrt{3})^2 = 25 - 3 = 22 \] The final answer is 22, which is placed in the answer box.
**Problem Statement:**

Divide. Show your work to receive full credit.

\[
\frac{2+\sqrt{2}}{2-\sqrt{3}}
\]

**Instructions:**

To divide and simplify the expression given, you should multiply both the numerator and the denominator by the conjugate of the denominator. The conjugate of \(2 - \sqrt{3}\) is \(2 + \sqrt{3}\). 

**Steps:**

1. Multiply both the numerator and the denominator by the conjugate of the denominator:
   
   \[
   \frac{(2+\sqrt{2})(2+\sqrt{3})}{(2-\sqrt{3})(2+\sqrt{3})}
   \]

2. Expand both the numerator and the denominator:

   - **Numerator:** \( (2+\sqrt{2})(2+\sqrt{3}) = 4 + 2\sqrt{3} + 2\sqrt{2} + \sqrt{6} \)

   - **Denominator:** \( (2-\sqrt{3})(2+\sqrt{3}) = 4 - 3 = 1 \)

3. Simplify the expression:

   Since the denominator is 1, the expression simplifies to the expanded numerator:

   \[
   4 + 2\sqrt{3} + 2\sqrt{2} + \sqrt{6}
   \]

Thus, the division results in the simplified expression \(4 + 2\sqrt{3} + 2\sqrt{2} + \sqrt{6}\).
Transcribed Image Text:**Problem Statement:** Divide. Show your work to receive full credit. \[ \frac{2+\sqrt{2}}{2-\sqrt{3}} \] **Instructions:** To divide and simplify the expression given, you should multiply both the numerator and the denominator by the conjugate of the denominator. The conjugate of \(2 - \sqrt{3}\) is \(2 + \sqrt{3}\). **Steps:** 1. Multiply both the numerator and the denominator by the conjugate of the denominator: \[ \frac{(2+\sqrt{2})(2+\sqrt{3})}{(2-\sqrt{3})(2+\sqrt{3})} \] 2. Expand both the numerator and the denominator: - **Numerator:** \( (2+\sqrt{2})(2+\sqrt{3}) = 4 + 2\sqrt{3} + 2\sqrt{2} + \sqrt{6} \) - **Denominator:** \( (2-\sqrt{3})(2+\sqrt{3}) = 4 - 3 = 1 \) 3. Simplify the expression: Since the denominator is 1, the expression simplifies to the expanded numerator: \[ 4 + 2\sqrt{3} + 2\sqrt{2} + \sqrt{6} \] Thus, the division results in the simplified expression \(4 + 2\sqrt{3} + 2\sqrt{2} + \sqrt{6}\).
Expert Solution
Step 1

Concept:

When the provided fraction has a radical term or a surd in the denominator, we rationalize the denominator. Square root and cube root are two examples of these radical words. The numerator and denominator of a mathematical statement containing two terms must both be multiplied by the conjugate of the denominator if the denominator contains a radical. Rationalization is the name of this technique.

steps

Step by step

Solved in 2 steps

Blurred answer
Similar questions
Recommended textbooks for you
Algebra and Trigonometry (6th Edition)
Algebra and Trigonometry (6th Edition)
Algebra
ISBN:
9780134463216
Author:
Robert F. Blitzer
Publisher:
PEARSON
Contemporary Abstract Algebra
Contemporary Abstract Algebra
Algebra
ISBN:
9781305657960
Author:
Joseph Gallian
Publisher:
Cengage Learning
Linear Algebra: A Modern Introduction
Linear Algebra: A Modern Introduction
Algebra
ISBN:
9781285463247
Author:
David Poole
Publisher:
Cengage Learning
Algebra And Trigonometry (11th Edition)
Algebra And Trigonometry (11th Edition)
Algebra
ISBN:
9780135163078
Author:
Michael Sullivan
Publisher:
PEARSON
Introduction to Linear Algebra, Fifth Edition
Introduction to Linear Algebra, Fifth Edition
Algebra
ISBN:
9780980232776
Author:
Gilbert Strang
Publisher:
Wellesley-Cambridge Press
College Algebra (Collegiate Math)
College Algebra (Collegiate Math)
Algebra
ISBN:
9780077836344
Author:
Julie Miller, Donna Gerken
Publisher:
McGraw-Hill Education