Algebra and Trigonometry (6th Edition)
6th Edition
ISBN:9780134463216
Author:Robert F. Blitzer
Publisher:Robert F. Blitzer
ChapterP: Prerequisites: Fundamental Concepts Of Algebra
Section: Chapter Questions
Problem 1MCCP: In Exercises 1-25, simplify the given expression or perform the indicated operation (and simplify,...
Related questions
Question
Multiplying and DIviding Radical Expressions
![**Task: Multiply**
Given the expression: \((5 + \sqrt{3})(5 - \sqrt{3}) = \) [Box with the answer 22]
**Explanation:**
This expression is a difference of squares. It can be simplified by using the formula:
\[
(a + b)(a - b) = a^2 - b^2
\]
In this case, \(a = 5\) and \(b = \sqrt{3}\).
Applying the formula:
\[
(5 + \sqrt{3})(5 - \sqrt{3}) = 5^2 - (\sqrt{3})^2 = 25 - 3 = 22
\]
The final answer is 22, which is placed in the answer box.](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2F7dc0f982-7a09-4dbe-930b-7bfa31cddbce%2F186f9628-a82a-414d-89df-7d954c531091%2Futa9rai_processed.png&w=3840&q=75)
Transcribed Image Text:**Task: Multiply**
Given the expression: \((5 + \sqrt{3})(5 - \sqrt{3}) = \) [Box with the answer 22]
**Explanation:**
This expression is a difference of squares. It can be simplified by using the formula:
\[
(a + b)(a - b) = a^2 - b^2
\]
In this case, \(a = 5\) and \(b = \sqrt{3}\).
Applying the formula:
\[
(5 + \sqrt{3})(5 - \sqrt{3}) = 5^2 - (\sqrt{3})^2 = 25 - 3 = 22
\]
The final answer is 22, which is placed in the answer box.
![**Problem Statement:**
Divide. Show your work to receive full credit.
\[
\frac{2+\sqrt{2}}{2-\sqrt{3}}
\]
**Instructions:**
To divide and simplify the expression given, you should multiply both the numerator and the denominator by the conjugate of the denominator. The conjugate of \(2 - \sqrt{3}\) is \(2 + \sqrt{3}\).
**Steps:**
1. Multiply both the numerator and the denominator by the conjugate of the denominator:
\[
\frac{(2+\sqrt{2})(2+\sqrt{3})}{(2-\sqrt{3})(2+\sqrt{3})}
\]
2. Expand both the numerator and the denominator:
- **Numerator:** \( (2+\sqrt{2})(2+\sqrt{3}) = 4 + 2\sqrt{3} + 2\sqrt{2} + \sqrt{6} \)
- **Denominator:** \( (2-\sqrt{3})(2+\sqrt{3}) = 4 - 3 = 1 \)
3. Simplify the expression:
Since the denominator is 1, the expression simplifies to the expanded numerator:
\[
4 + 2\sqrt{3} + 2\sqrt{2} + \sqrt{6}
\]
Thus, the division results in the simplified expression \(4 + 2\sqrt{3} + 2\sqrt{2} + \sqrt{6}\).](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2F7dc0f982-7a09-4dbe-930b-7bfa31cddbce%2F186f9628-a82a-414d-89df-7d954c531091%2Feq1lj4n_processed.png&w=3840&q=75)
Transcribed Image Text:**Problem Statement:**
Divide. Show your work to receive full credit.
\[
\frac{2+\sqrt{2}}{2-\sqrt{3}}
\]
**Instructions:**
To divide and simplify the expression given, you should multiply both the numerator and the denominator by the conjugate of the denominator. The conjugate of \(2 - \sqrt{3}\) is \(2 + \sqrt{3}\).
**Steps:**
1. Multiply both the numerator and the denominator by the conjugate of the denominator:
\[
\frac{(2+\sqrt{2})(2+\sqrt{3})}{(2-\sqrt{3})(2+\sqrt{3})}
\]
2. Expand both the numerator and the denominator:
- **Numerator:** \( (2+\sqrt{2})(2+\sqrt{3}) = 4 + 2\sqrt{3} + 2\sqrt{2} + \sqrt{6} \)
- **Denominator:** \( (2-\sqrt{3})(2+\sqrt{3}) = 4 - 3 = 1 \)
3. Simplify the expression:
Since the denominator is 1, the expression simplifies to the expanded numerator:
\[
4 + 2\sqrt{3} + 2\sqrt{2} + \sqrt{6}
\]
Thus, the division results in the simplified expression \(4 + 2\sqrt{3} + 2\sqrt{2} + \sqrt{6}\).
Expert Solution
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Step 1
Concept:
When the provided fraction has a radical term or a surd in the denominator, we rationalize the denominator. Square root and cube root are two examples of these radical words. The numerator and denominator of a mathematical statement containing two terms must both be multiplied by the conjugate of the denominator if the denominator contains a radical. Rationalization is the name of this technique.
Step by step
Solved in 2 steps
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