MULTIPLE CHOICE. Choose the one alternative that best completes the statement or answers the question. Vrite a polynomial f(x) in complete factored form that satisfies the conditions. Let the leading coefficient be 1. i) 1) Degree 4; zeros: -6 with multiplicity 3, and 8 with multiplicity 1 A) f(x) = (x - 8)3(x - 6) C) f(x) = (x + 8)3(x - 6) B) f(x) = (x - 6)3(x + 8) D) f(x) = (x + 6)3(x - 8) tate the end behavior of the graph of f. ii) f(x) = 5x3 A) Down on left side, up on right side C) Up on left side, down on right side B) Up on both sides D) Down on both sides ind the domain of f. ji) f(x) = X - 4 (x - 8)(x + 8) A) {x I x * 4} C) {x I x + -8, x * 8} B) {x I x + 8, x + -8} D) {x I x * -4

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A: we solve this problem using synthetic division, look at step 2

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Polynomials

Try substituting 1. You will get 6 and not 0. Try other real values also. What About -2? Let us check.