Multiple Choice O Reject the null hypothesis and conclude that the mean is equal to $6,000 per day. Reject the null hypothesis and conclude the mean is lower than $6,000 per day. Reject the null hypothesis and conclude the mean is higher than $6,000 per day. Fail to reject the null hypothesis.

Glencoe Algebra 1, Student Edition, 9780079039897, 0079039898, 2018
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Chapter10: Statistics
Section10.4: Distributions Of Data
Problem 19PFA
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TB MC Qu. 10-67 (Static) Sales at a fast-food restaurant average...
Sales at a fast-food restaurant average $6,000 per day. The restaurant decided to introduce an advertising campaign to increase daily sales. To
determine the effectiveness of the advertising campaign, a sample of 49 days of sales were taken. They found that the average daily sales were
$6,300 per day. From past history, the restaurant knew that its population standard deviation is about $1,000. The restaurant wishes to test
whether sales have increased as a result of the advertising campaign. If the level of significance is 0.05, what is the decision?
Multiple Choice
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O
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Reject the null hypothesis and conclude that the mean is equal to $6,000 per day.
Reject the null hypothesis and conclude the mean is lower than $6,000 per day.
Reject the null hypothesis and conclude the mean is higher than $6,000 per day.
Fail to reject the null hypothesis.
Transcribed Image Text:O TB MC Qu. 10-67 (Static) Sales at a fast-food restaurant average... Sales at a fast-food restaurant average $6,000 per day. The restaurant decided to introduce an advertising campaign to increase daily sales. To determine the effectiveness of the advertising campaign, a sample of 49 days of sales were taken. They found that the average daily sales were $6,300 per day. From past history, the restaurant knew that its population standard deviation is about $1,000. The restaurant wishes to test whether sales have increased as a result of the advertising campaign. If the level of significance is 0.05, what is the decision? Multiple Choice O O O Reject the null hypothesis and conclude that the mean is equal to $6,000 per day. Reject the null hypothesis and conclude the mean is lower than $6,000 per day. Reject the null hypothesis and conclude the mean is higher than $6,000 per day. Fail to reject the null hypothesis.
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