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Multiple Choice о O The probability of a 1 bit is 0.6; hence, the required probability is (6)¹0.06. The probability of a 1 bit is 0.6; hence, the required probability is 100.6≈ 3.9810. The probability of a 1 bit is 0.6; hence, the required probability is 0.6¹0≈ 0.0060. The probability of a 1 bit is 0.6; hence, the required probability is 0.60.6 x 110 0.736.

Multiple Choice о O The probability of a 1 bit is 0.6; hence, the required probability is (6)¹0.06. The probability of a 1 bit is 0.6; hence, the required probability is 100.6≈ 3.9810. The probability of a 1 bit is 0.6; hence, the required probability is 0.6¹0≈ 0.0060. The probability of a 1 bit is 0.6; hence, the required probability is 0.60.6 x 110 0.736.

Advanced Engineering Mathematics
Advanced Engineering Mathematics
10th Edition
ISBN:9780470458365
Author:Erwin Kreyszig
Publisher:Erwin Kreyszig
Chapter2: Second-order Linear Odes
Section: Chapter Questions
Problem 1RQ
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**Required Information** **Note:** This is a multi-part question. Once an answer is submitted, you will be unable to return to this part. Find the probability that a randomly generated bit string of length 10 does not contain a 0 if bits are independent and if the probability that a bit is a 1 is 0.6. --- ### Multiple Choice - **Option 1:** The probability of a 1 bit is 0.6; hence, the required probability is \( \left(\frac{0.6}{10}\right)^1 \approx 0.06 \). - **Option 2:** The probability of a 1 bit is 0.6; hence, the required probability is \( 10^{0.6} \approx 3.9810 \). - **Option 3:** The probability of a 1 bit is 0.6; hence, the required probability is \( 0.6^{10} \approx 0.0060 \). - **Option 4:** The probability of a 1 bit is 0.6; hence, the required probability is \( 0.6^{10} \times 1^{10} \approx 0.736 \).
Transcribed Image Text:**Required Information** **Note:** This is a multi-part question. Once an answer is submitted, you will be unable to return to this part. Find the probability that a randomly generated bit string of length 10 does not contain a 0 if bits are independent and if the probability that a bit is a 1 is 0.6. --- ### Multiple Choice - **Option 1:** The probability of a 1 bit is 0.6; hence, the required probability is \( \left(\frac{0.6}{10}\right)^1 \approx 0.06 \). - **Option 2:** The probability of a 1 bit is 0.6; hence, the required probability is \( 10^{0.6} \approx 3.9810 \). - **Option 3:** The probability of a 1 bit is 0.6; hence, the required probability is \( 0.6^{10} \approx 0.0060 \). - **Option 4:** The probability of a 1 bit is 0.6; hence, the required probability is \( 0.6^{10} \times 1^{10} \approx 0.736 \).
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