MTBE, a gasoline additive, undergoes combustion according to the following equation: 2 C5H12O (liq) + 15 O2 (g) → 10 CO2 (g) + 12 H2O (liq). Calculate ΔH for this reaction given the following three reactions: O2 (g) + 10 C (s) + 12 H2 (g) → 2 C5H12O ΔH = -627.2 kJ O2 (g) + C (s) → CO2 (g) ΔH = -393.5 kJ 2 H2 (g) + O2 (g) → 2 H2O (liq) ΔH = -571.6 kJ Select one: -6737.4 kJ -7991.8 kJ -337.8 kJ +6737.4 none of the other answers are correct.
MTBE, a gasoline additive, undergoes combustion according to the following equation: 2 C5H12O (liq) + 15 O2 (g) → 10 CO2 (g) + 12 H2O (liq). Calculate ΔH for this reaction given the following three reactions: O2 (g) + 10 C (s) + 12 H2 (g) → 2 C5H12O ΔH = -627.2 kJ O2 (g) + C (s) → CO2 (g) ΔH = -393.5 kJ 2 H2 (g) + O2 (g) → 2 H2O (liq) ΔH = -571.6 kJ Select one: -6737.4 kJ -7991.8 kJ -337.8 kJ +6737.4 none of the other answers are correct.
Chemistry
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ISBN:9781305957404
Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Chapter1: Chemical Foundations
Section: Chapter Questions
Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...
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MTBE, a gasoline additive, undergoes combustion according to the following equation:
2 C5H12O (liq) + 15 O2 (g) → 10 CO2 (g) + 12 H2O (liq).
Calculate ΔH for this reaction given the following three reactions:
O2 (g) + 10 C (s) + 12 H2 (g) → 2 C5H12O ΔH = -627.2 kJ
O2 (g) + C (s) → CO2 (g) ΔH = -393.5 kJ
2 H2 (g) + O2 (g) → 2 H2O (liq) ΔH = -571.6 kJ
2 C5H12O (liq) + 15 O2 (g) → 10 CO2 (g) + 12 H2O (liq).
Calculate ΔH for this reaction given the following three reactions:
O2 (g) + 10 C (s) + 12 H2 (g) → 2 C5H12O ΔH = -627.2 kJ
O2 (g) + C (s) → CO2 (g) ΔH = -393.5 kJ
2 H2 (g) + O2 (g) → 2 H2O (liq) ΔH = -571.6 kJ
Select one:
-6737.4 kJ
-7991.8 kJ
-337.8 kJ
+6737.4
none of the other answers are correct.
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