Ms. Norah had some biscuits in a tin. The number of biscuits were fewer than 60 but more than 40. She would have 2 biscuits left if she divided the biscuits equally among 10 children. She would also have 2 biscuits left if she divided the biscuits equally among 8 children. How many biscuits were in the tin? * Use the table below to help you solve the word problem Divide among 10 Divide among 8 Number of biscuits Check children children 7r 3 (3 biscuits left) 5r9 ex 1: 59 (9 biscuits left)

Algebra and Trigonometry (6th Edition)
6th Edition
ISBN:9780134463216
Author:Robert F. Blitzer
Publisher:Robert F. Blitzer
ChapterP: Prerequisites: Fundamental Concepts Of Algebra
Section: Chapter Questions
Problem 1MCCP: In Exercises 1-25, simplify the given expression or perform the indicated operation (and simplify,...
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Ms. Norah had some biscuits in a tin. The number of biscuits were fewer than 6O
but more than 40. She would have 2 biscuits left if she divided the biscuits
equally among 10 children. She would also have 2 biscuits left if she divided the
biscuits equally among 8 children. How many biscuits were in the tin? *
Use the table below to help
you solve the word problem
Divide among 10
Divide among 8
Number of biscuits
Check
children
children
7r 3
(3 biscuits left)
5r9
ex1: 59
(9 biscuits left)
6r 4
(4 biscuits left)
5r2
Sx.2 52
(2 biscuits left)
Transcribed Image Text:Ms. Norah had some biscuits in a tin. The number of biscuits were fewer than 6O but more than 40. She would have 2 biscuits left if she divided the biscuits equally among 10 children. She would also have 2 biscuits left if she divided the biscuits equally among 8 children. How many biscuits were in the tin? * Use the table below to help you solve the word problem Divide among 10 Divide among 8 Number of biscuits Check children children 7r 3 (3 biscuits left) 5r9 ex1: 59 (9 biscuits left) 6r 4 (4 biscuits left) 5r2 Sx.2 52 (2 biscuits left)
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