?m/s 60kg 0 m/s 40kg 요 v = 1.5 m/s

College Physics
11th Edition
ISBN:9781305952300
Author:Raymond A. Serway, Chris Vuille
Publisher:Raymond A. Serway, Chris Vuille
Chapter1: Units, Trigonometry. And Vectors
Section: Chapter Questions
Problem 1CQ: Estimate the order of magnitude of the length, in meters, of each of the following; (a) a mouse, (b)...
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Conservation of momentum
The image illustrates a physics problem involving conservation of momentum, depicted through stick figures on skateboards.

**Diagram Explanation:**

*Initial Situation:*
- On the left side, two individuals are depicted:
  - Person 1: Has a mass of 60 kg and is moving at an unknown velocity (? m/s) to the right.
  - Person 2: Has a mass of 40 kg and is stationary with a velocity of 0 m/s.

*Final Situation:*
- On the right side, both individuals are now together on the skateboard, moving in the same direction:
  - Combined velocity (v) is 1.5 m/s to the right.

### Key Concepts:
- **Conservation of Momentum:** The total momentum before the interaction equals the total momentum after the interaction.
- **Equation Setup:**
  - Initial Momentum = (60 kg * ? m/s) + (40 kg * 0 m/s)
  - Final Momentum = (60 kg + 40 kg) * 1.5 m/s

This example illustrates how to apply momentum conservation to determine unknown quantities in a system.
Transcribed Image Text:The image illustrates a physics problem involving conservation of momentum, depicted through stick figures on skateboards. **Diagram Explanation:** *Initial Situation:* - On the left side, two individuals are depicted: - Person 1: Has a mass of 60 kg and is moving at an unknown velocity (? m/s) to the right. - Person 2: Has a mass of 40 kg and is stationary with a velocity of 0 m/s. *Final Situation:* - On the right side, both individuals are now together on the skateboard, moving in the same direction: - Combined velocity (v) is 1.5 m/s to the right. ### Key Concepts: - **Conservation of Momentum:** The total momentum before the interaction equals the total momentum after the interaction. - **Equation Setup:** - Initial Momentum = (60 kg * ? m/s) + (40 kg * 0 m/s) - Final Momentum = (60 kg + 40 kg) * 1.5 m/s This example illustrates how to apply momentum conservation to determine unknown quantities in a system.
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