Mr. Thomas owns a rectangular property that Is 52 feet long and 35 feet wide. He adds a new triangular property directly behind his existing property. The base length of the triangular property is equal to the length of the rectangular property. An aerial view of the whole property is shown. 35 ft. 52 ft. The area of the whole property is 2,600 square feet. Based on the diagram, what is the maximum height, in feet, of the triangular property?

Algebra and Trigonometry (6th Edition)
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ISBN:9780134463216
Author:Robert F. Blitzer
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ChapterP: Prerequisites: Fundamental Concepts Of Algebra
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Problem 1MCCP: In Exercises 1-25, simplify the given expression or perform the indicated operation (and simplify,...
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Mr. Thomas owns a rectangular property that Is 52 feet long and 35
feet wide. He adds a new triangular property directly behind his
existing property. The base length of the triangular property is equal
to the length of the rectangular property. An aerial view of the whole
property is shown.
24.
35 ft.
52 ft.
The area of the whole property is 2,600 square feet. Based on the
diagram, what is the maximum height, in feet, of the triangular
property?
@ 15.0 feet
© 22.3 feet
© 30.0 feet
© 44.3 feet
Transcribed Image Text:Mr. Thomas owns a rectangular property that Is 52 feet long and 35 feet wide. He adds a new triangular property directly behind his existing property. The base length of the triangular property is equal to the length of the rectangular property. An aerial view of the whole property is shown. 24. 35 ft. 52 ft. The area of the whole property is 2,600 square feet. Based on the diagram, what is the maximum height, in feet, of the triangular property? @ 15.0 feet © 22.3 feet © 30.0 feet © 44.3 feet
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