Mr. Muscedere is driving his truck at a speed of 4.1m/s in the heading of (E47N]. He notices a squirrel and turns his truck to head [W67N] at the same speed. It takes him 2.2s to change his direction. What was his average acceleration during the "swerve"?
Mr. Muscedere is driving his truck at a speed of 4.1m/s in the heading of (E47N]. He notices a squirrel and turns his truck to head [W67N] at the same speed. It takes him 2.2s to change his direction. What was his average acceleration during the "swerve"?
University Physics Volume 1
18th Edition
ISBN:9781938168277
Author:William Moebs, Samuel J. Ling, Jeff Sanny
Publisher:William Moebs, Samuel J. Ling, Jeff Sanny
Chapter4: Motion In Two And Three Dimensions
Section: Chapter Questions
Problem 80AP: A particle travels m a circular orbit of radius 10 m. Its speed is changing at a rate of 15.0m/s2 at...
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Please answer question and just send me the paper solutions asap dont type the answer question 14 asap please and use 9.81 please ASAP 10 muns only
![Question 14
Mr. Muscedere is driving his truck at a speed of 4.1m/s in the heading of (E47N]. He
notices a squirrel and turns his truck to head [W67N] at the same speed. It takes him
2.2s to change his direction. What was his average acceleration during the
"swerve"?](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2Fa6289ac7-8d2f-40ca-af87-0712b96551a5%2Fe262f4f1-e86f-4a10-ba49-75b5f20c1432%2Fqtyf75p_processed.jpeg&w=3840&q=75)
Transcribed Image Text:Question 14
Mr. Muscedere is driving his truck at a speed of 4.1m/s in the heading of (E47N]. He
notices a squirrel and turns his truck to head [W67N] at the same speed. It takes him
2.2s to change his direction. What was his average acceleration during the
"swerve"?
![Ff = µF,
sinA
sinB
sinc
Fnet = ma
a2 = b2 + c2 – 2bccosA
a
C
V2 = V1 + aAt
Ad
Ad = V,At + %aA Ad = vAt - %aAt²
Vay =
t.
Ad = %(v1 + V2)At
g = 9.81
(v2) = (Vi} + 2aAd
472r
%3D
ac =
4n rf2
%3D
T2](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2Fa6289ac7-8d2f-40ca-af87-0712b96551a5%2Fe262f4f1-e86f-4a10-ba49-75b5f20c1432%2Fpsnk6n8_processed.jpeg&w=3840&q=75)
Transcribed Image Text:Ff = µF,
sinA
sinB
sinc
Fnet = ma
a2 = b2 + c2 – 2bccosA
a
C
V2 = V1 + aAt
Ad
Ad = V,At + %aA Ad = vAt - %aAt²
Vay =
t.
Ad = %(v1 + V2)At
g = 9.81
(v2) = (Vi} + 2aAd
472r
%3D
ac =
4n rf2
%3D
T2
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