Mr. Basset finally got a new lock to keep people from stealing things from his gym locker! While setting his lock up, he has to create a 4 number code using the numbers 1-20 in any position. How many code possibilities are there? Which strategy would be appropriate for this situation? Select three answers from the list below. Combination 20 19 18 17 20 20 20 20 Neither permutation nor combination 20! 1614! 20! 16! 204 Permutation 20! 4! 20-19-18-17 000000

Algebra and Trigonometry (6th Edition)
6th Edition
ISBN:9780134463216
Author:Robert F. Blitzer
Publisher:Robert F. Blitzer
ChapterP: Prerequisites: Fundamental Concepts Of Algebra
Section: Chapter Questions
Problem 1MCCP: In Exercises 1-25, simplify the given expression or perform the indicated operation (and simplify,...
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## Problem Statement:
Mr. Basset finally got a new lock to keep people from stealing things from his gym locker! While setting his lock up, he has to create a 4-number code using the numbers 1-20 in any position. How many code possibilities are there?

### Which strategy would be appropriate for this situation?

### Select three answers from the list below.

1. [ ] Combination 
   
2. [ ] 20 19 18 17

3. [ ] 20 20 20 20

4. [ ] Neither permutation nor combination

5. [ ] \(\frac{20!}{16!}\)

6. [ ] \(\frac{20!}{16}\)

7. [ ] \(20^4\)

8. [ ] Permutation

9. [ ] \(\frac{20!}{4!}\)

10. [ ] \(\frac{20 \cdot 19 \cdot 18 \cdot 17}{4!}\)
Transcribed Image Text:## Problem Statement: Mr. Basset finally got a new lock to keep people from stealing things from his gym locker! While setting his lock up, he has to create a 4-number code using the numbers 1-20 in any position. How many code possibilities are there? ### Which strategy would be appropriate for this situation? ### Select three answers from the list below. 1. [ ] Combination 2. [ ] 20 19 18 17 3. [ ] 20 20 20 20 4. [ ] Neither permutation nor combination 5. [ ] \(\frac{20!}{16!}\) 6. [ ] \(\frac{20!}{16}\) 7. [ ] \(20^4\) 8. [ ] Permutation 9. [ ] \(\frac{20!}{4!}\) 10. [ ] \(\frac{20 \cdot 19 \cdot 18 \cdot 17}{4!}\)
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